Question

我有一个Java项目，该项目具有几个依赖项，例如：

dependencies {
    compile("com.whatever.jar:jar-1:1.2.3")
    compile("com.whatever.jar:jar-2:4.5.6")
    compile("com.whatever.jar:jar-3:7.8.9")
}

我将其打包为jar库，并将其与描述这些依赖项的POM文件一起发布到存储库中：

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>
    <groupId>com.my.project</groupId>
    <artifactId>my-library</artifactId>
    <version>1.0.0</version>
    <dependencies>
        <dependency>
            <groupId>com.whatever.jar</groupId>
            <artifactId>jar-1</artifactId>
            <version>1.2.3</version>
            <scope>compile</scope>
        </dependency>
        <dependency>
            <groupId>com.whatever.jar</groupId>
            <artifactId>jar-2</artifactId>
            <version>4.5.6</version>
            <scope>compile</scope>
        </dependency>
        <dependency>
            <groupId>com.whatever.jar</groupId>
            <artifactId>jar-3</artifactId>
            <version>7.8.9</version>
            <scope>compile</scope>
        </dependency>
    </dependencies>
</project>

我还有一个另一个项目，该项目取决于以前在编译时构建的jar：

dependencies {
    compileOnly("com.my.project:my-library:1.0.0")
}

我想创建一个构建第二个项目的任务，并创建一个包含com.my.project:my-library:1.0.0 jar及其传递依赖项（jar-1，jar-2和jar-3的zip文件。）。

task createZip << {
    into('lib') {
        // here I would like to do something like (it's a horrible pseudo-code):
        from configurations.(com.my.project:my-library:1.0.0).jar.transitiveDependencies.files
    }
}

我该如何实现？

编辑：我还想以编程方式访问my-library的传递性依赖项列表（正是这些，而不是项目中的任何其他依赖项），以便使用以下方式建立Loader-Path清单属性那些。

Answer 1

这是一个自包含的build.gradle脚本，它演示了如何创建createZip任务（该任务仅向ZIP存档添加特定的依赖项）：

/* make the "compileOnly" configuration available */
plugins {
    id 'java'
}

/* add some demo dependencies to the project */
repositories {
    jcenter()
}
dependencies {
    compileOnly 'junit:junit:4.12'
    compileOnly 'org.slf4j:slf4j-simple:1.7.28'
}

task createZip(type: Zip) {
    // the "lib" directory in the ZIP file will only have all those dependency
    // files of the "compileOnly" configuration which belong to the
    // "junit:junit:4.12" module:
    def depOfInterest = dependencies.create('junit:junit:4.12')
    into('lib') {
        from configurations.compileOnly.resolvedConfiguration.getFiles({dep ->
            dep == depOfInterest
        })
    }

    // the "justForDemonstration" directory in the ZIP file will have all
    // dependency files of the "compileOnly" configuration, incl. SLF4J:
    into('justForDemonstration') {
        from configurations.compileOnly
    }
}

这可以与./gradlew createZip一起运行（已通过Gradle 5.6.2测试）。它在build/distributions/<your_project_name>.zip下生成ZIP文件。让我知道您是否打算使用伪代码。

Answer 2

var existingIbans = AccountRepository
    .GetAll()
    .Select(acc => acc.Iban)
    .ToHashSet();

var allIbans = lines
    .Select(line => line.Split(';')[1]);

var newIbans = allIbans
    .Where(iban => !existingIbans.Contains(iban));

foreach (var iban in newIbans)
{
    AccountRepository.AddAccount(new Account(iban));
    Save();
}

Gradle在目录中包含传递依赖项

2 个答案: