Question

我有2个值，我想过滤数据中的那些值。我该怎么办？

我要过滤ID 1和2。

    data: [
            {id: 1, name: "Carl", city: "New York"},
            {id: 2, name: "Anna", city: "New York"},
            {id: 3, name: "Carl", city: "Sydney"}
        ]

    filterValue: [1, 2]

Answer 1

您可以将.filter()与.includes()一起使用，以检查obj.filterValue是否具有当前对象id，如果没有，则可以保留数组，如果它会从新数组中删除它：

const obj = {data:[{id:1,name:"Carl",city:"New York"},{id:2,name:"Anna",city:"New York"},{id:3,name:"Carl",city:"Sydney"}],filterValue:[1,2]};
const res = obj.data.filter(({id}) => !obj.filterValue.includes(id));

console.log(res);

Answer 2

您可以使用此实用程序功能，该功能使用要过滤的值的数组和要过滤的对象的键：

const data = [{ id: 1, name: 'Carl', city: 'New York' }, { id: 2, name: 'Anna', city: 'New York' }, { id: 3, name: 'Carl', city: 'Sydney' }]

const filterData = (d, f, k) => data.filter(o => f.includes(o[k]))

console.log(filterData(data, [1, 2], 'id'))
console.log(filterData(data, ['Carl'], 'name'))

Answer 3

使用data作为键，从id中生成哈希映射。

let data = [
        {id: 1, name: "Carl", city: "New York"},
        {id: 2, name: "Anna", city: "New York"},
        {id: 3, name: "Carl", city: "Sydney"}
    ];
let map1 = new Map(data.map(e=>[e.id,e]));
let filterValue = [1, 2];
let output = filterValue.map(e=>map1.get(e));
console.log(output);

Answer 4

使用interface Option { title: string; isSelected?: boolean; } function myFunc(options: Option[]): void {} const options: Option[] = [{title: 'Male', isSelected: true}, {title: 'Female'}, {title: 'Other'}]; const options2 = {...options}; myFunc(options); myFunc(options2); // why isn't this an error ?和filter来过滤另一个数组中的值

indexOf

Answer 5

您可以在Array上使用.filter（）：

var data = [{
    id: 1,
    name: "Carl",
    city: "New York"
  },
  {
    id: 2,
    name: "Anna",
    city: "New York"
  },
  {
    id: 3,
    name: "Carl",
    city: "Sydney"
  }
]

var filteredData = data.filter(function(data) {     
    return data.id == 1 || data.id == 2;
})

如何在JS中应用多个过滤器和多个值？

5 个答案: