MERGE INTO TABLE1 t1
USING TABLE2 t2
ON (t1.ID = t2.ID)
WHEN MATCHED THEN UPDATE
SET t1.PHONE_NUMBER = CASE
WHEN t1.type in ('A','B') THEN t2.phone_number
ELSE NVL(t2.phone_number, t1.phone_number)
END
需要将MERGE
以上的内容转换为UPDATE
语句。
我尝试了以下方法:
UPDATE TABLE1 t1
SET t1.PHONE_NUMBER = (
SELECT t2.PHONE_NUMBER
FROM TABLE2 t2, TABLE1 t3
WHERE t3.type in ('A','B')
AND t3.ID = t2.ID
)
如何在以上实现中合并CASE
?
答案 0 :(得分:1)
MERGE
语句将更加高效,您应该使用它;但是,您可以使用:
UPDATE table1 t1
SET PHONE_NUMBER = NVL(
( SELECT t2.phone_number
FROM table2 t2
WHERE t1.id = t2.id ),
CASE
WHEN t1.type IN ( 'A', 'B' )
THEN NULL
ELSE t1.phone_number
END
)
WHERE EXISTS ( SELECT 1 FROM table2 t2 WHERE t1.id = t2.id );
Oracle设置:
CREATE TABLE table1 ( id, phone_number, type ) AS
SELECT 1, 123456, 'A' FROM DUAL UNION ALL
SELECT 2, 123456, 'B' FROM DUAL UNION ALL
SELECT 3, 123456, 'C' FROM DUAL UNION ALL
SELECT 4, 123456, 'D' FROM DUAL UNION ALL
SELECT 5, 123456, 'E' FROM DUAL;
CREATE TABLE table2 ( id, phone_number ) AS
SELECT 1, 234567 FROM DUAL UNION ALL
SELECT 2, NULL FROM DUAL UNION ALL
SELECT 3, 345678 FROM DUAL UNION ALL
SELECT 4, NULL FROM DUAL;
输出:
运行更新后,然后:
SELECT * FROM table1
与MERGE
语句输出相同:
ID | PHONE_NUMBER | TYPE -: | -----------: | :--- 1 | 234567 | A 2 | null | B 3 | 345678 | C 4 | 123456 | D 5 | 123456 | E
db <>提琴here
更新:
如果您查看EXPLAIN PLAN
语句的MERGE
:
| PLAN_TABLE_OUTPUT | | :------------------------------------------------------------------------------ | | Plan hash value: 3423411568 | | | | ------------------------------------------------------------------------------- | | | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | | | ------------------------------------------------------------------------------- | | | 0 | MERGE STATEMENT | | 4 | 168 | 7 (15)| 00:00:01 | | | | 1 | MERGE | TABLE1 | | | | | | | | 2 | VIEW | | | | | | | | |* 3 | HASH JOIN | | 4 | 268 | 7 (15)| 00:00:01 | | | | 4 | TABLE ACCESS FULL| TABLE2 | 4 | 104 | 3 (0)| 00:00:01 | | | | 5 | TABLE ACCESS FULL| TABLE1 | 5 | 205 | 3 (0)| 00:00:01 | | | ------------------------------------------------------------------------------- >
然后,它仅读取一次TABLE1
和TABLE2
。
将其与EXPLAIN PLAN
语句的UPDATE
比较:
| PLAN_TABLE_OUTPUT | | :----------------------------------------------------------------------------- | | Plan hash value: 735598124 | | | | ------------------------------------------------------------------------------ | | | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | | | ------------------------------------------------------------------------------ | | | 0 | UPDATE STATEMENT | | 4 | 168 | 23 (22)| 00:00:01 | | | | 1 | UPDATE | TABLE1 | | | | | | | |* 2 | HASH JOIN SEMI | | 4 | 168 | 7 (15)| 00:00:01 | | | | 3 | TABLE ACCESS FULL| TABLE1 | 5 | 145 | 3 (0)| 00:00:01 | | | | 4 | TABLE ACCESS FULL| TABLE2 | 4 | 52 | 3 (0)| 00:00:01 | | | |* 5 | TABLE ACCESS FULL | TABLE2 | 1 | 26 | 3 (0)| 00:00:01 | | | ------------------------------------------------------------------------------ |
然后它将从TABLE1
读取一次,并从TABLE2
读取两次;因此MERGE
可能是一个性能更高的查询...。但是,如果需要,您可以使用UPDATE
进行查询。
db <>提琴here
答案 1 :(得分:1)
您可以在RIGHT JOIN
中使用这样的嵌套子查询:
update table1 t
set t.phone_number = (
select tt.phone_number
from(
select case
when t1.type in ('A','B') then t2.phone_number
else nvl(t2.phone_number, t1.phone_number)
end as phone_number,
nvl(t2.ID,t1.ID) as ID
from table2 t2
right join table1 t1
on t1.ID = nvl(t2.ID,t1.ID)
) tt
where tt.ID = t.ID
);
感谢您的小提琴@MTO