序列化查询对象数组多对多关系

Question

我遇到了在续集中查询多对多关系的问题

@Table
export class Video extends Model<Video> {

    @Unique
    @PrimaryKey
    @AutoIncrement
    @Column
    id!: number;

    @Column
    imageUrl!: string;

    @Column
    url!: string;

    @Column
    title!: string;

    @Column
    description!: string;

    @BelongsToMany(() => Tag, () => VideoTag)
    tags?: Tag[];
}

@Table
export class Tag extends Model<Tag> {

    @Unique
    @PrimaryKey
    @AutoIncrement
    @Column
    id!: number;

    @Column
    title!: string;

    @BelongsToMany(() => Video, () => VideoTag)
    videos?: Video[];
}

@Table
export class VideoTag extends Model<VideoTag> {

    @ForeignKey(() => Video)
    @Column
    videoId!: number;

    @ForeignKey(() => Tag)
    @Column
    tagId!: number;
}

给出一个查询字符串，我想返回其中queryString是video.title或video.tags[*].title的子字符串的视频列表 这是我目前拥有的东西，但是不起作用

export function searchVideo(req: any, res: any, next: any) {
    if (req.query.q) {
        const queryString = req.query.q.toLowerCase();
        Video.findAll({
            limit:10,
            include: [{
               model: Tag
            }],
            where: {
                [Op.or]: [
                    {
                        title: {
                            [Op.like]: `%${queryString}%`
                        }
                    },
                    {
                        tags: [ {
                            title: {
                                [Op.like]: `%${queryString}%`
                            }
                        }]
                    }
                ]
            }
        })
            .then((videos) => {
                res.send(videos)
            })
            .catch(err => {
                console.log(err);
                res.setHeader('Content-Type', 'application/json');
                res.statusCode = 400;
                res.send(`{"errorMessage": "${err}"}`)
            })
    } else {
        res.redirect('/videos');
    }
}

我得到Error: Invalid value { title: { [Symbol(like)]: '%j%' } }
有人可以帮忙吗？asdasdas