Question

我试图在一个方法中多次使用一个PHP实例变量，但只有第一个显示一个值，其余的什么都不返回。什么是正确的方法。查看示例代码

<? class Foo{
private $variable;

  //constructor
  public function __construct($variable){
    $this->variable = $variable;
  }

  //method
  public function renderVariable(){
    echo "first use of the variable".$this->variable; //shows the variable when method is called
    echo "subsequent use of the variable".this->variable; //shows nothing
  }

}
?>

假设上面的类另存为Foo.php并在下面调用

<html>
<head>
<title></title>
</head>
<body>
<?
include 'Foo.php';
$x = Foo(37);
$x->renderVariable();//prints two lines, the first includes 37, the second does not
?>
</body>

当前，我必须将实例传递给方法中的局部变量，请参见下文

<? class Foo{
private $variable;

  //constructor
  public function __construct($variable){
    $this->variable = $variable;
  }

  //method
  public function renderVariable(){
    $y=$this->variable;
    echo "first use of the variable".$y; //shows the variable when method is called
    echo "subsequent use of the variable".$y; //shows the variable when method is called
  }

}
?>

多次使用PHP实例变量的正确方法是什么

0 个答案: