我在awk脚本中遇到问题-我需要生成一个报告，其中包含数据文件中每个作业的最低，最高和平均分数。分配的名称位于column 3中。
输入数据为：
Student,Catehory,Assignment,Score,Possible
Chelsey,Homework,H01,90,100
Chelsey,Homework,H02,89,100
Chelsey,Homework,H03,77,100
Chelsey,Homework,H04,80,100
Chelsey,Homework,H05,82,100
Chelsey,Homework,H06,84,100
Chelsey,Homework,H07,86,100
Chelsey,Lab,L01,91,100
Chelsey,Lab,L02,100,100
Chelsey,Lab,L03,100,100
Chelsey,Lab,L04,100,100
Chelsey,Lab,L05,96,100
Chelsey,Lab,L06,80,100
Chelsey,Lab,L07,81,100
Chelsey,Quiz,Q01,100,100
Chelsey,Quiz,Q02,100,100
Chelsey,Quiz,Q03,98,100
Chelsey,Quiz,Q04,93,100
Chelsey,Quiz,Q05,99,100
Chelsey,Quiz,Q06,88,100
Chelsey,Quiz,Q07,100,100
Chelsey,Final,FINAL,82,100
Chelsey,Survey,WS,5,5
Sam,Homework,H01,19,100
Sam,Homework,H02,82,100
Sam,Homework,H03,95,100
Sam,Homework,H04,46,100
Sam,Homework,H05,82,100
Sam,Homework,H06,97,100
Sam,Homework,H07,52,100
Sam,Lab,L01,41,100
Sam,Lab,L02,85,100
Sam,Lab,L03,99,100
Sam,Lab,L04,99,100
Sam,Lab,L05,0,100
Sam,Lab,L06,0,100
Sam,Lab,L07,0,100
Sam,Quiz,Q01,91,100
Sam,Quiz,Q02,85,100
Sam,Quiz,Q03,33,100
Sam,Quiz,Q04,64,100
Sam,Quiz,Q05,54,100
Sam,Quiz,Q06,95,100
Sam,Quiz,Q07,68,100
Sam,Final,FINAL,58,100
Sam,Survey,WS,5,5
Andrew,Homework,H01,25,100
Andrew,Homework,H02,47,100
Andrew,Homework,H03,85,100
Andrew,Homework,H04,65,100
Andrew,Homework,H05,54,100
Andrew,Homework,H06,58,100
Andrew,Homework,H07,52,100
Andrew,Lab,L01,87,100
Andrew,Lab,L02,45,100
Andrew,Lab,L03,92,100
Andrew,Lab,L04,48,100
Andrew,Lab,L05,42,100
Andrew,Lab,L06,99,100
Andrew,Lab,L07,86,100
Andrew,Quiz,Q01,25,100
Andrew,Quiz,Q02,84,100
Andrew,Quiz,Q03,59,100
Andrew,Quiz,Q04,93,100
Andrew,Quiz,Q05,85,100
Andrew,Quiz,Q06,94,100
Andrew,Quiz,Q07,58,100
Andrew,Final,FINAL,99,100
Andrew,Survey,WS,5,5
Ava,Homework,H01,55,100
Ava,Homework,H02,95,100
Ava,Homework,H03,84,100
Ava,Homework,H04,74,100
Ava,Homework,H05,95,100
Ava,Homework,H06,84,100
Ava,Homework,H07,55,100
Ava,Lab,L01,66,100
Ava,Lab,L02,77,100
Ava,Lab,L03,88,100
Ava,Lab,L04,99,100
Ava,Lab,L05,55,100
Ava,Lab,L06,66,100
Ava,Lab,L07,77,100
Ava,Quiz,Q01,88,100
Ava,Quiz,Q02,99,100
Ava,Quiz,Q03,44,100
Ava,Quiz,Q04,55,100
Ava,Quiz,Q05,66,100
Ava,Quiz,Q06,77,100
Ava,Quiz,Q07,88,100
Ava,Final,FINAL,99,100
Ava,Survey,WS,5,5
Shane,Homework,H01,50,100
Shane,Homework,H02,60,100
Shane,Homework,H03,70,100
Shane,Homework,H04,60,100
Shane,Homework,H05,70,100
Shane,Homework,H06,80,100
Shane,Homework,H07,90,100
Shane,Lab,L01,90,100
Shane,Lab,L02,0,100
Shane,Lab,L03,100,100
Shane,Lab,L04,50,100
Shane,Lab,L05,40,100
Shane,Lab,L06,60,100
Shane,Lab,L07,80,100
Shane,Quiz,Q01,70,100
Shane,Quiz,Q02,90,100
Shane,Quiz,Q03,100,100
Shane,Quiz,Q04,100,100
Shane,Quiz,Q05,80,100
Shane,Quiz,Q06,80,100
Shane,Quiz,Q07,80,100
Shane,Final,FINAL,90,100
Shane,Survey,WS,5,5
awk脚本：
BEGIN {
FS=" *\\, *"
}
FNR>1 {
min[$3]=(!($3 in min) || min[$3]> $4 )? $4 : min[$3]
max[$3]=(max[$3]> $4)? max[$3] : $4
cnt[$3]++
sum[$3]+=$4
}
END {
print "Name\tLow\tHigh\tAverage"
for (i in cnt)
printf("%s\t%d\t%d\t%.1f\n", i, min[i], max[i], sum[i]/cnt[i])
}
预期的样本输出：
Name Low High Average
Q06 77 95 86.80
L05 40 96 46.60
WS 5 5 5
Q07 58 100 78.80
L06 60 99 61
L07 77 86 64.80
运行脚本时，所有分配的“低”为0，这是不正确的。我要去哪里错了？请指导。
答案 0 :(得分：0)
您当然可以使用awk来执行此操作，但是由于您也标记了此脚本，因此我假设可以使用其他工具。对于这种有关数据中存在的组的统计信息收集，GNU datamash通常将工作简化为简单的一线工作。例如：
$ (echo Name,Low,High,Average; datamash --header-in -s -t, -g3 min 4 max 4 mean 4 < input.csv) | tr , '\t'
Name Low High Average
FINAL 58 99 85.6
H01 19 90 47.8
H02 47 95 74.6
H03 70 95 82.2
H04 46 80 65
H05 54 95 76.6
H06 58 97 80.6
H07 52 90 67
L01 41 91 75
L02 0 100 61.4
L03 88 100 95.8
L04 48 100 79.2
L05 0 96 46.6
L06 0 99 61
L07 0 86 64.8
Q01 25 100 74.8
Q02 84 100 91.6
Q03 33 100 66.8
Q04 55 100 81
Q05 54 99 76.8
Q06 77 95 86.8
Q07 58 100 78.8
WS 5 5 5
这表示，对于每个具有相同第三列值的组（-g3，再加上-s对简单CSV输入（{{1 }}）和标题（-t,），显示第4列的最小值，最大值和平均值。所有这些都赋予了新的标题，并通过管道传递到--header-in以将逗号变成制表符。
答案 1 :(得分：0)
您的代码可以与GNU awk一样使用。但是，使用-t选项运行它以警告不可移植的构造会给出：
awk: foo.awk:6: warning: old awk does not support the keyword `in' except after `for'
awk: foo.awk:2: warning: old awk does not support regexps as value of `FS'
并以不同的awk实现运行脚本（在我的情况下为mawk），对于Low列给出的值为0。因此，请对该脚本进行一些调整：
BEGIN {
FS=","
}
FNR>1 {
min[$3]=(cnt[$3] == 0 || min[$3]> $4 )? $4 : min[$3]
max[$3]=(max[$3]> $4)? max[$3] : $4
cnt[$3]++
sum[$3]+=$4
}
END {
print "Name\tLow\tHigh\tAverage"
PROCINFO["sorted_in"] = "@ind_str_asc" # gawk-ism for pretty output; ignored on other awks
for (i in cnt)
printf("%s\t%d\t%d\t%.1f\n", i, min[i], max[i], sum[i]/cnt[i])
}
，它也可以在其他awk上正常工作。
cnt[$3]是否等于0（这是第一次，因为该值在后面的一行），或者如果当前最小值大于此值。答案 2 :(得分：0)
另一种类似的方法
$ awk -F, 'NR==1 {print "name","low","high","average"; next}
{k=$3; sum[k]+=$4; count[k]++}
!(k in min) {min[k]=max[k]=$4}
min[k]>$4 {min[k]=$4}
max[k]<$4 {max[k]=$4}
END {for(k in min) print k,min[k],max[k],sum[k]/count[k]}' file |
column -t
name low high average
Q06 77 95 86.8
L05 0 96 46.6
WS 5 5 5
Q07 58 100 78.8
L06 0 99 61
L07 0 86 64.8
H01 19 90 47.8
H02 47 95 74.6
H03 70 95 82.2