Question

DB::table('job_post')->insert(['user_id'=>$user->id,'job_title'=>$data['job_title'],'job_skill'=>$data['skill'],'max_sal'=>$data['max_sal'],'min_sal'=>$data['min_sal'],'job_type'=>$data['job_type'],'shift'=>$data['shift'],'last_date'=>$data['last_date'],'job_image'=>$imagename,'job_description'=>$data['job_description'],'latitude'=>$data['latitude'],'longitude'=>$data['longitude'],'location'=>$data['location']]);
            //return redirect()->to('employer/congrats/......here i want id of job_post which i create');
            return view('employer/congrats',compact('id','navbar_data'));

Answer 1

是的，您可以通过insertGetId获取Laravel中最后插入的ID：

$id = DB::table('users')->insertGetId(
    array('email' => 'john@example.com', 'votes' => 0)
);

return redirect('employer/congrats',compact('id','navbar_data'));

Answer 2

您可以尝试这样的事情

DB::table('job_post')->insert([
    // ... data to insert e.g. 'user_id' => $user->id,
]);
$id = DB::getPdo()->lastInsertId();

return view('employer.congrats', compact('id','navbar_data'));

或

const array = [
    ['a', 'b', 'c'],
    ['d', 'e'],
    ['f', 'g', 'h', 'i', 'j'],
    ['k'],
    ['l'],
    ['m'],
    ['n', 'o', 'p'],
    ['q', 'r', 's'],
    ['t', 'u', 'v'],
    ['x']
];


function shuffle(arr) { /* Shuffling algorithm here */ }

shuffle(array);

// Extracts arrays with exactly "count" elements, excluding all elements in "exclude" and starting at "start" in the array
// If no combination was found, return undefined
function takeOut(array, count, start = 0, exclude = []) {
  // Base case: Count wasn't reached exactly, abort here
  if(count < 0) return;
  // Base case: Combination was found, go up
  if(count === 0) return [];

  // Go over the array to find a matching combination
  for(let i = start; i < array.length; i++) {
    const current = array[i];
    // Skip elements that should be excluded
    if(exclude.includes(current)) continue;
    
    // Recursive call: Find more elements so that a group of "count" gets reached
    const rest = takeOut(array, count - current.length, i + 1, exclude);
    if(!rest) continue; // If this element can't be matched up, go on
    return [current, ...rest];
  }
}

// Our two teams:
const first = takeOut(array, 5);
const second = takeOut(array, 5, 0, first); // all from the first team can't be in the second one

console.log(first, second);

if(first && second)
   console.log("The game can start");

有关更多信息，请查看this博客文章。

是否有可能我创建帖子并且还想在laravel中创建后重定向到同一帖子

2 个答案: