Question

运行代码时，它会按计划要求输入，但是未定义列表alpha。

首先，输入内容未读取，因此我更改了缩进方式，但是没有解决定义问题。

def newclassification1(alpha,bravo):
        alpha = ["Jacob", "Jane", "Jim"]
        bravo = ["Male", "Female", "Unknown"]

    name = input("What is the persons name?")
    if name in alpha:
        while True:
            print(bravo[alpha.index(name)])
    else:
        print("The persons name is not in the register.")

错误消息：

回溯（最近一次通话最后一次）：文件“”，第7行，在 NameError：名称“ alpha”未定义

Answer 1

我做了一些调整，主要是从函数中删除alpha和bravo。

alpha = ["Jacob", "Jane", "Jim"]
bravo = ["Male", "Female", "Unknown"]
def newclassification1(alpha,bravo):
    name = input("What is the persons name?")
    if name in alpha:
        print(bravo[alpha.index(name)])
    else:
        print("The persons name is not in the register.")
newclassification1(alpha,bravo)

之所以可行，是因为由于您要将alpha和bravo传递给函数，因此这些变量应在函数外部定义。另外，我将您的while更改为if，因为否则，您将获得无限的输出。我要共享的功能的输出：

What is the persons name?Jim
Unknown
What is the persons name?Jane
Female
What is the persons name?a
The persons name is not in the register.

给出OP注释：alpha和bravo 必须必须在功能中定义。

def newclassification1(alpha = [],bravo = []):
    alpha = ["Jacob", "Jane", "Jim"]
    bravo = ["Male", "Female", "Unknown"]
    name = input("What is the persons name?")
    if name in alpha:
        print(bravo[alpha.index(name)])
    else:
        print("The persons name is not in the register.")
newclassification1()

输出：

What is the persons name?Jim
Unknown
What is the persons name?Tim
The persons name is not in the register.
What is the persons name?Jane
Female

Answer 2

我不知道您的最终目的，但是这两个代码在 Python3 上没有任何错误。

第一个：

def newclassification1(alpha,bravo):
    name = input("What is the persons name?")
    if name in alpha:
        while True:
            print(bravo[alpha.index(name)])
    else:
        print("The persons name is not in the register.")

newclassification1(["Jacob", "Jane", "Jim"], ["Male", "Female", "Unknown"])

第二个：

def newclassification1(alpha,bravo):
    alpha = ["Jacob", "Jane", "Jim"]
    bravo = ["Male", "Female", "Unknown"]
    name = input("What is the persons name?")
    if name in alpha:
        while True:
            print(bravo[alpha.index(name)])
    else:
        print("The persons name is not in the register.")

newclassification1([], [])

Answer 3

def newclassification1(name):
    alpha = ["Jacob", "Jane", "Jim"]
    bravo = ["Male", "Female", "Unknown"]
    if name in alpha:
        print(bravo[alpha.index(name)])
    else:
        print("The persons name is not in the register.")

name = input("What is the persons name?")

newclassification1(name)

Answer 4

正如其他人指出的那样，您应该修复缩进，并找出带有您的论点的东西。首先，当您在函数中定义add_action( 'admin_enqueue_scripts', create_function( '', "wp_enqueue_style( 'pb_backupbuddy-wp-admin', '" . pb_backupbuddy::plugin_url() . "/css/wp-admin.css', array(), pb_backupbuddy::settings( 'version' ) );" )和alpha时，每次调用它们都将被重写，我想您不想发生这种情况。其次，您应该修复缩进。我建议您具备以下条件：

bravo

通过这种方式，默认情况下，您将使用def newclassification1(alpha=["Jacob", "Jane", "Jim"],bravo=["Male", "Female", "Unknown"]): name = input("What is the persons name?") if name in alpha: print(bravo[alpha.index(name)]) else: print("The persons name is not in the register.")和alpha=["Jacob", "Jane", "Jim"]，但是稍后调用该函数时，可以轻松地将其更改为所需的内容。

此外，您不需要bravo=["Male", "Female", "Unknown"]部分，因为它将在不停止执行的情况下运行

Answer 5

扩展Celius答案：

alpha = ["Jacob", "Jane", "Jim"]
bravo = ["Male", "Female", "Unknown"]
def newclassification1(alpha,bravo):
    name = input("What is the persons name?")
    print(bravo[alpha.index(name)] if (name in alpha) else "xxxxx")
newclassification1(alpha,bravo)

只需使用Python三元运算并将结果直接发送到print语句

访问在函数内部定义的列表

5 个答案: