Question

如果满足条件，我会尝试将此列乘以数字。如果是，我希望将august_report ['每月定期收费']列乘以20之类的数字。

declare @xml as nvarchar(max)

set @xml = N'<monthdate>2019-07-01</monthdate>
<automitemno>302</automitemno>
<amount>1.190000000000</amount>
<currentamount>0.000000000000</currentamount>
<langitemno>1</langitemno>
<monthdate>2019-07-01</monthdate>
<automitemno>2131</automitemno>
<amount>0.386750000000</amount>
<currentamount>0.000000000000</currentamount>
<langitemno>1</langitemno>'


select replace(substring(a.value, charindex('<monthdate>',a.value)+11, charindex('</amount>', a.value)-16), char(10), '') as [XMLValue]

from string_split(replace(@xml, '</langitemno>', char(30)), char(30)) a

where a.value like '%<monthdate>%</amount>%'

Answer 1

IIUC，这就是您要寻找的

august_report['Activation Commission'] = np.where((august_report['Line activity'] == 'Activation')&(august_report['Activation type'] == 'Lease'),august_report['Activation Commission']*august_report['Monthly Recurring Charge'],"a number")

Answer 2

IIUC，这就是您想要的：

august_report['Activation Commission'] = np.where((august_report['Line activity'] == 'Activation')&(august_report['Activation type'] == 'Lease'),august_report['Monthly Recurring Charge']*20, 'condition not met'))

如果要在不满足条件时保留原始值，请用'condition not met'替换august_report['Monthly Recurring Charge']

如果满足np.where，则将新列乘以数字

2 个答案: