我需要使用Java 8将<String, List<String>>
映射到Map<String,String>
,并假定值是唯一的。例如,
输入图-
{"Fruit" -> ["apple","orange"], "Animal" -> ["Dog","Cat"]}
输出图
{"apple" -> "Fruit", "orange" -> "Fruit", "Dog"->"Animal", "Cat" -> "Animal"}
Map <String, String> outputMap = new HashMap<>();
for (Map.Entry<String, List<String>> entry : inputMap.entrySet()) {
entry.getValue().forEach(value -> outputMap.put(value, entry.getKey()));
}
这是对的吗?我们可以使用Java 8流实现这一点吗?
答案 0 :(得分:0)
这样做:
public class InverterMap {
public static void main(String[] args) {
Map<String, List<String>> mp = new HashMap<String, List<String>>();
mp.put("Fruit", Arrays.asList("Apple", "Orange"));
mp.put("Animal", Arrays.asList("Dog", "Cat"));
System.out.println(mp); // It returned {Fruit=[Apple, Orange], Animal=[Dog, Cat]}
Map<String, String> invertMap = mp.entrySet().stream().collect(HashMap::new,
(m, v) -> v.getValue().forEach(k -> m.put(k, v.getKey())), Map::putAll);
System.out.println(invertMap);// It returned {Apple=Fruit, Cat=Animal, Orange=Fruit, Dog=Animal}
}
}
阅读Stream.collect(Supplier supplier, BiConsumer, BiConsumer combiner)了解更多信息。
答案 1 :(得分:0)
您可以这样尝试
Map <String, String> updatedMap = new HashMap<>();
oldMap.keySet()
.forEach(i -> oldMap.get(i)
.forEach(k -> updatedMap.put(k, i)));