我有一个字符串列表的列表。看起来像这样:
fetchFilter
我想进一步将每个字符串嵌套在列表中,所以看起来像这样:
console.log
请告知如何执行此操作。谢谢。
答案 0 :(得分:1)
使用以下列表理解
[[[s2] for s2 in s1] for s1 in l]
运行示例:
>>> l = [['okay'],
['d', 'so'],
['i', 'guess']]
>>> [[[s2] for s2 in s1] for s1 in l]
[[['okay']], [['d'], ['so']], [['i'], ['guess']]]