Question

我正在尝试在php中建立一个访客计数器。...

我不知道每天如何重新计数或重置计数器，因为可用的计数器仅计数一次

我的代码现在看起来像这样：

不确定该代码是否有效，但需要一些想法或建议。谢谢

<?php
date_default_timezone_set("Asia/Kuala_Lumpur");//grab timezone
$now = date("H:i");
echo $now;
echo "<br>";

if($now == "00:00"){//when the clock is 00:00 count will be 0 again
    $count = 0;
}
?>
<?php
session_start(); 
if(!isset($_SESSION['counter'])) { // It's the first visit in this session
    $handle = fopen("counter.txt", "r");
    if(!$handle){
        echo "Could not open the file" ;
    }
    else {
        $counter = ( int ) fread ($handle,20) ;
        fclose ($handle) ;
        $counter++ ;
        echo" <p> Visitor Count: ". $counter . " </p> " ;
        $handle = fopen("counter.txt", "w" ) ;
        fwrite($handle,$counter) ;
        fclose ($handle) ;
        $_SESSION['counter'] = $counter;
    }

} else { // It's not the first time, do not update the counter but show the total hits stored in session
    $counter = $_SESSION['counter'];
    echo" <p> Visitor Count: ". $counter . " </p> " ;
}
?>

我的目标是每天显示访客人数。 p / s：一些代码来自stackoverflow。

Answer 1

只有在服务器时间正好00:00有人访问您的网站时，您的代码才有可能正常工作。

您将需要cronjob或类似的名称，以在00:00重置.txt中的计数器，而与页面访问无关。

Answer 2

您可以在文件中添加当天。检索数据时，如果文件中的日期不同，则为当天的首次访问，可以重置计数器：

date_default_timezone_set("Asia/Kuala_Lumpur");//grab timezone
$today = date("Y-m-d"); // get current date

session_start(); 
if(!isset($_SESSION['counter'])) { // It's the first visit in this session
    $handle = fopen("counter.txt", "r");
    if(!$handle){
        echo "Could not open the file" ;
    }
    else {
        // retrieve the data
        $line = fread($handle,20) ;
        fclose ($handle) ;
        $parts = explode(' ', $line);
        $date = $parts[0]; // retrieve date in file
        $counter = intval($parts[1]); // retrieve visit in file

        // reset if first visit at a new day
        if($date != $today)
        {
            $counter = 0 ;
        }

        // save the new date/counter data
        $counter++ ;
        echo" <p> Visitor Count: ". $counter . " </p> " ;
        $handle = fopen("counter.txt", "w" ) ;

        $newdata= $today . ' ' . $counter ; // put today + counter in the file
        fwrite($handle,$newdata) ;
        fclose ($handle) ;
        $_SESSION['counter'] = $counter;
    }

} else { // It's not the first time, do not update the counter but show the total hits stored in session
    $counter = $_SESSION['counter'];
    echo" <p> Visitor Count: ". $counter . " </p> " ;
}

Answer 3

在stackoverflow上找到了它。

它的工作原理与我想要的完全一样。

谢谢您的帮助。

<?php
$filename = date("Ymd") . "_counter.txt";
$seenFilename = date("Ymd") . '_seen_ip.txt';

$ips = array();
if (file_exists($seenFilename))
{
    $ips = file($seenFilename);
    $ips = array_map('trim', $ips);
}

if(!in_array($_SERVER['REMOTE_ADDR'], $ips))
{
    $visits = 0;
    if (file_exists($filename)) {
        $visits = file_get_contents($filename);
    }

    file_put_contents($filename, ++$visits);
    $data = $_SERVER['REMOTE_ADDR'] . PHP_EOL;
    $fp = fopen($seenFilename, 'a');
    fwrite($fp, $data);
}
$fn = fopen($filename, "r");
$result = fgets($fn);
echo $result;
fclose($fn);
?>

p / s：一些代码来自stackoverflow。

计算唯一身份访问者并每天重置计数器，而无需使用数据库

3 个答案: