JSON iPhone - 帮助

Question

我可以从Web服务中获取以下JSON数据。

问题：

1. 是否应该返回正确的JSON格式？
2. 我不知道在xcode上找回这些数据？

有人能帮我吗？

非常感谢。

http://192.168.11.6/specificRegion.php?region_ID=011

[{"idReference_no":"R00008","Region_ID":"011","HouseMall_Name_In_Chinese":"A","Rental_Month":"0","Rental_Hour":"0","Rental_Fee_Month":"0.00","Rental_Fee_Hour":"0.00"}, {"idReference_no":"R00009","Region_ID":"011","HouseMall_Name_In_Chinese":"B","Rental_Month":"0","Rental_Hour":"0","Rental_Fee_Month":"0.00","Rental_Fee_Hour":"0.00"}, {"idReference_no":"R00010","Region_ID":"011","HouseMall_Name_In_Chinese":"C","Rental_Month":"0","Rental_Hour":"0","Rental_Fee_Month":"0.00","Rental_Fee_Hour":"0.00"}, {"idReference_no":"R00011","Region_ID":"011","HouseMall_Name_In_Chinese":"D","Rental_Month":"0","Rental_Hour":"0","Rental_Fee_Month":"0.00","Rental_Fee_Hour":"0.00"}]

Answer 1

对于第一个问题：您始终可以在jsonlint.com检查json对象的有效性。如果您是Chrome用户，请查看JSONView Chrome扩展程序。要在xcode项目中使用JSON，请参阅this question。