为什么重命名的函数不能像R中的原始函数那样工作

时间:2019-09-25 20:38:24

标签: r function dataframe formula

我正在使用factanal将名为efa的BASE R函数重命名为match.call。但是我想知道为什么仅在对公式x使用公式时,efa会引发错误:object 'n.obs' not foundfactanal正常工作?

注意:将data.frame用作x时,efa可以正常工作。

efa <- function(x, factors, data = NULL, covmat = NULL, n.obs = NA,
            subset, na.action, start = NULL, center = FALSE,
            scores = c("none", "regression", "Bartlett"),
            rotation = "varimax", control = NULL, ...)
 {

 fit <- factanal(x, factors, data = data, covmat, n.obs = n.obs,
              subset, na.action, start = start,
              scores = scores,
              rotation = rotation, control = control, ...)

 fit$call <- match.call(expand.dots = FALSE)

 return(fit)
}

# Example of use:

v1 <- c(1,1,1,1,1,1,1,1,1,1,3,3,3,3,3,4,5,6)
v2 <- c(1,2,1,1,1,1,2,1,2,1,3,4,3,3,3,4,6,5)
v3 <- c(3,3,3,3,3,1,1,1,1,1,1,1,1,1,1,5,4,6)

factanal(~v1+v2+v3, factors = 1, data = data.frame(v1, v2, v3)) # Works fine
     efa(~v1+v2+v3, factors = 1, data = data.frame(v1, v2, v3)) # Error: object 'n.obs' not found

     efa(data.frame(v1, v2, v3), factors = 1) # Works fine

1 个答案:

答案 0 :(得分:2)

我认为更通用的方法是先捕获调用,包装所有参数,然后对其求值。像这样

efa <- function(x, factors, data = NULL, covmat = NULL, n.obs = NA,
                subset, na.action, start = NULL, center = FALSE,
                scores = c("none", "regression", "Bartlett"),
                rotation = "varimax", control = NULL, ...)
{

  cc <- match.call(expand.dots = FALSE)
  cc[[1]] <- quote(factanal)
  fit <- eval.parent(cc)
  fit$call <- match.call(expand.dots = FALSE)

  return(fit)
}

我们可以测试

efa(~v1+v2+v3, factors = 1, data = data.frame(v1, v2, v3))
# Call:
# efa(x = ~v1 + v2 + v3, factors = 1, data = data.frame(v1, v2,     v3))
# 
# Uniquenesses:
#    v1    v2    v3 
# 0.005 0.114 0.739 
# 
# Loadings:
#    Factor1
# v1 0.998  
# v2 0.941  
# v3 0.511  
# 
#                Factor1
# SS loadings      2.143
# Proportion Var   0.714
# 
# The degrees of freedom for the model is 0 and the fit was 0.0609 

此功能无法正常运行的原因是,当您将值传递给n.obs时,它假定这是data.frame中包含您要使用的值的变量的名称,并不能认为这是您当前环境中的变量。