Question

我在python上执行了排序功能，但是我写两次如何修复它的“ 2”呢？

liste = [10,200,5,2,3]
minimal = []
w = 0
try:
    sayac = 0
    lent= (len(liste)-1)
    while True:
        sayac += 1
        if lent == sayac:
            break
        else:  
            listelen = (len(liste)-1)
            for i in liste:
                if i <= liste[w] and i <= liste[listelen] and i <= liste[int(listelen/2)]:
                    minimal.append(i)
                else:
                    pass
            print(minimal)
            lent = (len(minimal)-1)
            for i in liste:
                if i == minimal[lent]:
                    liste.remove(i)
                else:
                    pass
except:
    print(minimal)

 OUT : [2, 3, 2, 5, 10, 200]
  [2, 3, 2, 5, 10, 200]
...

我的“ liste”值是1，但是它写了两次，我该如何解决？我的大脑现在消失了

Answer 1

因为在第一步中添加了多个minimal，但随后仅从liste中删除了最后一个：

liste = [10,200,5,2,3]
minimal = []
w = 0
try:
    sayac = 0
    lent= (len(liste)-1)
    while True:
        sayac += 1
        if lent == sayac:
            break
        else:  
            listelen = (len(liste)-1)
            for i in liste:
                if i <= liste[w] and i <= liste[listelen] and i <= liste[int(listelen/2)]:
                    minimal.append(i)
                    break ##########this line added
                else:
                    pass
            print(minimal)
            lent = (len(minimal)-1)
            for i in liste:
                if i == minimal[lent]:
                    liste.remove(i)
                else:
                    pass
except:
    print(minimal)

此外，我会重新考虑破坏条件，这样可能会更好：

liste = [10,200,5,2,3]
minimal = []
w = 0
try:
    sayac = 0
    lent= (len(liste)-1)
    while True:
        sayac += 1
        if len(liste)==0: ############condition changed
            break
        else:  
            listelen = (len(liste)-1)
            for i in liste:
                if i <= liste[w] and i <= liste[listelen] and i <= liste[int(listelen/2)]:
                    minimal.append(i)
                    break #############this line added
                else:
                    pass
            print(minimal)
            lent = (len(minimal)-1)
            for i in liste:
                if i == minimal[lent]:
                    liste.remove(i)
                else:
                    pass
except:
    print(minimal)

如何解决两次附加在列表中的问题

1 个答案: