我有以下SQL,并给我表达错误。
我想检查记录是否存在,如果存在,那么我想执行一个sql并获取列值,如果不存在,我想执行另一个sql并获取列值。
我该怎么做甲骨文?
DECLARE
VALIDEXISTS NUMBER;
BEGIN
SELECT *
FROM table1
WHERE column1 IN ('Yes')
AND columns2 IN (
SELECT COUNT(column1) AS VALIDEXISTS
FROM table1
WHERE column1 IN ('Yes')
AND column2 NOT LIKE '%Yes%'
IF VALIDEXISTS = 0 THEN
SELECT column2
FROM table1
WHERE column1 IN ('Yes')
AND column2 NOT LIKE '%Yes%'
ELSE
SELECT column2
FROM table1
WHERE column1 IN ('Yes')
AND column2 NOT LIKE '%No%' END IF; )
END
答案 0 :(得分:2)
首先计算条件,然后使用git restore -s@ -SW hello.c
将其应用于最终的SELECT
。像这样:
CASE