运行此命令后:
mtr -jnbz www.google.com |jq .report.hubs|jq -r 'keys_unsorted[] as $k | "\(.[$k])"'
我得到这个结果:
{"count":"1","host":"1.1.1.1","ASN":"AS???","Loss%":0,"Snt":10,"Last":36.28,"Avg":39.43,"Best":34.77,"Wrst":62.37,"StDev":8.15}
{"count":"2","host":"2.2.2.2","ASN":"AS???","Loss%":100,"Snt":10,"Last":0,"Avg":0,"Best":0,"Wrst":0,"StDev":0}
如何获得此结果(普罗米修斯格式):
mtr_loss{"count"="1","host"="1.1.1.1","ASN"="AS???"} 0
mtr_snt{"count"="1","host"="1.1.1.1","ASN"="AS???"} 10
mtr_last{"count"="1","host"="1.1.1.1","ASN"="AS???"} 36.28
mtr_avg{"count"="1","host"="1.1.1.1","ASN"="AS???"} 39.43
mtr_best{"count"="1","host"="1.1.1.1","ASN"="AS???"} 34.77
mtr_wrst{"count"="1","host"="1.1.1.1","ASN"="AS???"} 67.37
mtr_stdev{"count"="1","host"="1.1.1.1","ASN"="AS???"} 8.15
第二个字符串依此类推
对于任何提示和技巧,我将感激不尽
致谢
答案 0 :(得分:1)
以下内容可能更易于遵循,维护和重用:
# produce the {"k"="value", ...} representation:
def kv:
. as $in
| reduce keys_unsorted[] as $k ([]; . + ["\"\($k)\"=\"\($in[$k])\""] )
| join(",")
| "{" + . + "}" ;
# downcase and remove %
def ht($s):
keys_unsorted[] as $key
| .[$key] as $value
| "mtr_\($key|ascii_downcase|gsub("%";""))\($s) \($value)";
({count,host,ASN} | kv) as $s
| {"Loss%", Snt, Last, Avg, Best, Wrst, StDev}
| ht($s)
答案 1 :(得分:0)
这很容易:):
mtr -jnbz www.google.com |
tr -d "%" |
jq -r '.report.hubs[]
| "mtr_loss{count=\"\(.count)\",host=\"\(.host)\",asn=\"\(.ASN)\"} \(.Loss)\nmtr_sent{count=\"\(.count)\",host=\"\(.host)\",asn=\"\(.ASN)\"} \(.Snt)\nmtr_last{count=\"\(.count)\",host=\"\(.host)\",asn=\"\(.ASN)\"} \(.Last)\nmtr_avg{count=\"\(.count)\",host=\"\(.host)\",asn=\"\(.ASN)\"} \(.Avg)\nmtr_best{count=\"\(.count)\",host=\"\(.host)\",asn=\"\(.ASN)\"} \(.Best)\nmtr_wrst{count=\"\(.count)\",host=\"\(.host)\",asn=\"\(.ASN)\"} \(.Wrst)\nmtr_stdev{count=\"\(.count)\",host=\"\(.host)\",asn=\"\(.ASN)\"} \(.StDev)" '