Question

我有这个程序，要求用户输入两个数字，并检查数字之间的每个数字是否可以用5和7进行除法。如果范围内没有数字可以除以5和7，我希望程序输出“找不到数字”之类的内容。例如，如果用户输入3和4，它将显示“找不到号码”

我尝试了几种不同的方法，但是都没有用。

start = int(input("Start: "))
stop = int(input("Stop: "))


for number in range(start, (stop+1),1):
    if number % 5 == 0 and number % 7 ==0:
        print("Number", number, "can be divided with 5 and 7")
        print("Stop search")
        break
    elif  number % 5 == 0 and number % 7 !=0:
        print(number, "can't be divided with 7, next.")
    elif number % 5 != 0:
        print(number,"can't be divided with 5, next.")

Answer 1

您可以将else:子句与for循环一起使用。仅当整个for循环正常结束且未到达break子句时才执行该命令。在极少数情况下，它很有用！

for number in range(start, (stop+1),1):
    if number % 5 == 0 and number % 7 ==0:
        print("Number", number, "can be divided with 5 and 7")
        print("Stop search")
        break
    elif  number % 5 == 0 and number % 7 !=0:
        print(number, "can't be divided with 7, next.")
    elif number % 5 != 0:
        print(number,"can't be divided with 5, next.")
else:
    print("No number that can be divided by both 5 and 7 found.")

Answer 2

正如丹尼尔·罗斯曼（Daniel Roseman）所说，我也没有意识到else子句，所以我做了一个使用测试变量的破解方法

start = int(input("Start: "))
stop = int(input("Stop: "))

Test = 0
for number in range(start, (stop+1),1):
    if number % 5 == 0 and number % 7 ==0:
        print("Number", number, "can be divided with 5 and 7")
        print("Stop search")
        Test = 1
        break
    elif  number % 5 == 0 and number % 7 !=0:
        print(number, "can't be divided with 7, next.")
    elif number % 5 != 0:
        print(number,"can't be divided with 5, next.")


if Test == 0:
    print("no number in range")

Answer 3

为for循环添加一个布尔条件。

found = False

然后在发生for循环的停止条件时将此布尔值更改为true。

最后，根据发现的布尔条件执行操作，例如：

if !found:
    # Print when the value was not found.

[edit] ：RemcoGerlich发布的解决方案是更好的解决方案。

Answer 4

您还可以将变量用作标志，以告诉您是否找到该号码：

found = False
for number in range(start, (stop+1),1):
    if number % 5 == 0 and number % 7 ==0:
        print("Number", number, "can be divided with 5 and 7")
        print("Stop search")
        found = True
        break
    elif  number % 5 == 0 and number % 7 !=0:
        print(number, "can't be divided with 7, next.")
    elif number % 5 != 0:
        print(number,"can't be divided with 5, next.")

if not found:
    print("No number that can be divided by both 5 and 7 found.")

Python for循环结束，不满足任何条件

4 个答案: