我有一个代码正在处理并将两个文件夹（A和B）中的文件复制到8个不同的文件夹中，其中文件夹A中的文件进入4个文件夹，文件夹B中的文件进入到其他4个文件夹。
A和B的4个文件夹中的每个都有不同的名称，但文件夹名称中都包含A或B。
如何根据包含字符串的文件夹定义dest_path而不是定义实际路径？
此刻，我列出了dest_paths，但是试图通过包含A或B来定义它们；但无法了解如何将dest_path定义为循环，以将文件从原始A和B文件夹复制到其中
ppath = ("D:\\parent\\path\\to\\all\\content")
#want adest to say any folder that contains a and bdest to say any folder that contains b
adest = [(str(ppath) + "\\" + "A - Dest1"), (str(ppath) + "\\" + "A - Dest2"),
(str(ppath) + "\\" + "A - Dest3"),(str(ppath) + "\\" + "A - Dest4")]
bdest = [(str(ppath) + "\\" + "B - Dest1"), (str(ppath) + "\\" + "B - Dest2"),
(str(ppath) + "\\" + "B - Dest3"),(str(ppath) + "\\" + "B - Dest4")]
#####Trying to get paths to be defined by containing A or B#####
search_path = os.path.join(ppath + "\\")
astring = "A"
bstring = "B"
for file in os.listdir(search_path)
if astring in file:
dest_path = file
else:
dest_path = file
#Parent folder the A and B folders (todays date) and parent folders
dfolder = os.path.join(ppath + "\\" + "190924")
apath = os.path.join(dfolder + "\\" + "A")
bpath = os.path.join(dfolder + "\\" + "B")
#CopyBlock
for filename in os.listdir(dfolder):
if filename == ("A"):
for file in os.listdir(apath):
fulla_name = os.path.join(apath, file)
for path in adest:
shutil.copy(fulla_name, path)
elif filename == ("B"):
for file in os.listdir(bpath):
fullb_name = os.path.join(bpath, file)
for path in bdest:
shutil.copy(fullb_name, path)