谁能帮我完成这个python-if-else任务？

Question

Assignment image

import random

n = random.randint(1,100)
if (n % 2 != 0):
    print("Weird")
elif (n % 2 == 0 and n in range(2,5)):
    print("Not Weird")
elif (n % 2 == 0 and n in range(6,20)):
    print("Weird")
elif (n % 2 == 0 and n > 20):
    print("Not Weird")    

此代码是否有问题？

Answer 1

您的范围检查并不严格，例如：range(2, 5)包括介于2和4之间的整数，但是总有一种更简单的编写方法；试试这个：

import random    
n = random.randint(1,100)

if n % 2 != 0:
    print("Weird")
elif 2 <= n <= 5: # from this point on, the number can only be even
    print("Not Weird")
elif 6 <= n <= 20:
    print("Weird")
elif n > 20:
    print("Not Weird")

或更妙的是，它更简单，而且功能相同：

if n % 2 != 0 or 6 <= n <= 20:
    print("Weird")
else:
    print("Not Weird")

Answer 2

随机导入

n = random.randint(1,100)
print(n)
if (n % 2 != 0):
    print("Weird")
elif (n % 2 == 0 and n in range(2,5)):
    print("Not Weird")
elif (n % 2 == 0 and n in range(5,20)):
    print("Weird")
elif (n % 2 == 0 and n >= 20):
    print("Not Weird")

您错过了一些我刚刚更新了代码的范围。