Question

{
  "message" : "success ",
  "status" : "1",
  "Result" : {
    "name" : "abc",
    "lastname" : null,
    "middlename" : null,
    "id" : 20431
  }
}

我想使用模型以及如何检索结果对象将结果对象存储到单个用户默认值中

Answer 1

来自文档here。你有这样尝试过吗？

//convert the JSON to a raw String
if let rawString = json.rawString() {
    userDefaults.set(rawString, forKey: "jsonData")
} else {
    print("json.rawString is nil")
}

Answer 2

首先使用Codable协议为此创建一个模型

struct MyJSON : Codable {
    let message : String?
    let status : String?
    let result : JSONResult? // Don't use Result, a keyword in swift 
}

struct JSONResult : Codable {
    let name : String?
    let lastname : String?
    let middlename : String?
    let id : Int?
}

然后使用协议映射JSON，将模型保存在UserDefaults中。

let jsonString = 

"""
{
  "message" : "success ",
  "status" : "1",
  "result" : {
    "name" : "abc",
    "lastname" : null,
    "middlename" : null,
    "id" : 20431
}
}
"""


let jsonData = Data(jsonString.utf8)
let data = try JSONDecoder().decode(MyJSON.self, from: jsonData)


// save model in userDefaults 
func saveModel() {
    if let encoded = try? JSONEncoder().encode(data) {
    UserDefaults.standard.set(encoded, forKey: "MySavedValue")
   }

}


//get the model 

func getModel() -> MyJSON? {
     guard let data = UserDefaults.standard.object(forKey: "MySavedValue") as? Data else {
            return nil
        }
     return try? JSONDecoder().decode(MyJSON.self, from: data) 
}

使用方法

saveModel()

print(getModel()?.message) // print("Success")

将字典作为单个数组存储到userdefault中-Alamofire-SwiftyJSon

2 个答案: