Question

我有一个作业，要求我将十进制数转换为存储在char数组中的16位2的补码二进制表示形式。向我提供了包含完整的main方法和addOne方法的入门代码。我只需要完成flipBits和magnitudeToBinary方法。

我已经完成了这些方法，它们应该可以工作，但是我正在获取字符串输出。一个例子是：

Enter integers and convert it to 2's complement binary.
Non-numeric input terminates program.
27
Integer: 27, 2's complement binary:

代码如下：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>

void magnitudeToBinary(int n, char arr[], int numOfBits);
void flipBits(char arr[], int numOfBits);
void addOne(char arr[], int numOfBits);


int main(void) {
    setvbuf(stdout, NULL, _IONBF, 0);

    //Declare a char array with size 16 to simulate 16-bit binary
    int numOfBits = 16;
    char arr[numOfBits + 1];
    arr[numOfBits] = '\0'; //set the terminating character
    //Declare integer n to hold the decimal integer
    int n = 0;

    puts("Enter integers and convert it to 2's complement binary.");
    puts("Non-numeric input terminates program.");

    //Continually taking input and convert it to binary
    while (scanf("%d", &n) == 1) {//if successfully read in ONE decimal integer
        //Initialize the char array to all 0s (leave the terminating character unchanged)
        for(int i = 0; i < numOfBits; i ++){
            arr[i] = '0';
        }

        //Convert magnitude (absolute value) to binary
        magnitudeToBinary(abs(n), arr, numOfBits);

        //if the number is negative: flip all bits, then add 1.
        if(n < 0){
            //Flip all bits in char arr
            flipBits(arr, numOfBits);
            //Add 1
            addOne(arr, numOfBits);
        }
        //Output binary:
        printf("Integer: %d, 2's complement binary: %s\n", n, arr);
    }

    return EXIT_SUCCESS;
}
/* addOne: arithmatically add 1 to the binary simulated by character array
 * INPUT:   char arr[]: the character array holding the binary
 *          int numOfBits: the number of bits in the binary
 * */
void addOne(char arr[], int numOfBits){
    /* True table
     * ******************************
     * carry arr[i] |  arr[i] carry
     *  1       0   |   1       0
     *  1       1   |   0       1
     *  0       0   |   0       0
     *  0       1   |   1       0
     * *********************************/
    char carry = '1';
    for(int i = numOfBits - 1; i >= 0; i --){
        if(carry != arr[i]){
            arr[i] = '1';
            carry = '0';
        }
        else if(carry == '1'){
            arr[i] = '0';
        }
        else{
            arr[i] = '0';
        }
    }
    return;
}
/* flipBits: perform 1's complement on the binary, i.e., change 1 to 0, 0 to 1
 * INPUT:   char arr[]: the character array holding the binary
 *          int numOfBits: the number of bits in the binary *
 * */
void flipBits(char arr[], int numOfBits){
    //Implement your solution here
    for(int i = 0; i < numOfBits; i++) {
        if(arr[i] == '1') {
            arr[i] = '0';
        } else if(arr[i] == '0') {
            arr[i] = '1';
        }
    }
    return;
}
/* magnitudeToBinary:   Convert a non-negative decimal integer to binary (stored in a char array)
 *                      using division-remainder algorithm
 * INPUT:   int n: The decimal integer number to be converted
 *          char arr[]: the character array holding the binary
 *          int numOfBits: the number of bits in the binary *
 * */
void magnitudeToBinary(int n, char arr[], int numOfBits){
    //Implement the division-remainder algorithm here
    int i = 0;
    while (n > 0) {
        arr[i] = n % 2;
        n = n / 2;
        i++;
    }
    return;
}

我只想看到正确的二进制输出。现在，我不确定这是否是我本人，我的教授的错误，还是Eclipse在起作用。感谢您的任何帮助，谢谢！

Answer 1

尝试从以下位置改变那条线的大小：

    arr[i] = n % 2;

到

    arr[i] = n % 2 == 1 ? '1' : '0';

您想要将'1'或'0'的ASCII值写入数组-而不是n％2的结果。

为什么我的程序无法正确将小数转换为二进制打印？

1 个答案: