Question

试图从数组中删除多个对象，我做的解决方案很好并且可以工作，但是我想要的是我不想过滤两次，只想用一种方式

那么您能帮我获得最佳解决方案吗

示例

 const arrList = [{v:'1',l:'label1'},{v:'2',l:'label2'}, 
                  {v:'3',l:'label3'}, {v:'4',l:'label4'}, 
                  {v:'5',l:'label5'}]
const filter1 = arrList.filter((a) => a.l !== 'label1')
const filter3 = filter1.filter((a) => a.l !== 'label3')
console.log(filter3);

Answer 1

您正在使用2条语句进行过滤，第一条不等于label1，另一条语句label3。您可以使用AND &&运算符将它们合并为一条语句，如下所示

const filter1 = arrList.filter((a) => a.l !== 'label1' && a.l !== 'label3')

Answer 2

或者您可以使用更简单的解决方案：

arrList.filter((a) => !['label1', 'label3'].includes(a.l))

Answer 3

您可以使用.list-group-item-deleted { text-decoration: line-through }将逻辑语句组合成单个&&表达式：

filter()

Answer 4

尝试这样的事情！

 const arrList = [{v:'1',l:'label1'},{v:'2',l:'label2'}, 
                  {v:'3',l:'label3'}, {v:'4',l:'label4'}, 
                  {v:'5',l:'label5'}]
const filter1 = arrList.filter((a) => a.l !== 'label1' && a.l !== 'label3')
console.log(filter1);

Answer 5

const filter3 = arrList.filter（（a）=> a.l！=='label1'&& a.l！=='label3'）

Answer 6

您可以像这样过滤它。

public static double paintRequired(double totalSquareFeet){

    double paintNeeded = totalSquareFeet / 115;
    return paintNeeded;

                                                          }

public static double costOfPaint(double paintNeeded, double costOfPaint){
    double paintCost = paintNeeded * costOfPaint;
    return paintCost;
                                                    }


public static void main(String[] args){
    double costOfPaint = 0;
    int totalSquareFeet = 0;
    double paintNeeded = 0;

    Scanner getUserInput = new Scanner(System.in);

    System.out.println("what is the cost of the paint per gallon");
        costOfPaint = getUserInput.nextDouble();
    System.out.println("How many rooms do you need painted");
        int rooms = getUserInput.nextInt();
            for(int i = 1; i <= rooms; i++){
                System.out.println("how many square feet are in room:" + i);
                int roomSquareFeet = getUserInput.nextInt();
                totalSquareFeet = roomSquareFeet + totalSquareFeet;
                                           }

    System.out.println("the amount of paint needed:" + paintRequired(totalSquareFeet) + "gallons");
    System.out.println("the cost of the paint will be: " + costOfPaint(paintNeeded, costOfPaint));

}

从数组中删除多个对象并返回更新后的数组

6 个答案: