代码出错

Question

我想使用按钮进行操作。也就是说，如果我按下编辑或删除按钮，用户就会导航到action.php页面。写入删除或编辑查询的位置。我使用POST方法导航到action.php

action.php的

$remove = $_REQUEST['remove'];
if(isset($_POST["remove"])) {
$sql = "DELETE FROM t_s_list WHERE `s_id` ='$remove'";
mysql_query($sql);
    $NEW="This records is Deleted";
    //header("location: manage_song.php?msg=$NEW");
}

有点混淆了要传递什么值以将其与字段s_id

进行比较

Answer 1

可能是对应于表的主键的整数值，我假设..

Answer 2

打印$ _REQUEST ['删除'];并看到外面你可以看到通过值

Answer 3

if (isset($_POST["remove"]))
{
 $remove = mysql_real_escape_string($_POST["remove"],$link);
 $sql = "DELETE FROM t_s_list WHERE s_id ='$remove'";
 mysql_query($sql,$link);
 $NEW="This records is Deleted";
//header("location: manage_song.php?msg=$NEW");
}
else if (isset($_POST["edit"]))
{

}
else
 echo 'Invalid Request !';