Question

我正在制作一个连接到Amazon的AWS服务的应用程序。我的所有连接都正常，但是在连接之前我需要按下一个按钮。有没有办法避免此步骤并将其自动连接到AWS？

现在，用户必须按一个按钮，说他们想连接，然后按另一个按钮，他们想订阅一个主题以接收更新。该应用程序的唯一目的是连接到AWS，我想删除按钮按钮，因为这只是浪费时间。

这是我用来建立连接的教程，以防它提供更好的信息：https://www.linkedin.com/pulse/android-app-aws-iot-core-guide-felipe-ramos-da-silva

否则，这是我的代码：

@Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        this.context = PubSubActivity.this;

        //Sets up layout information
        txtSubscribe = (EditText) findViewById(R.id.txtSubscribe);
        tvClientId = (TextView) findViewById(R.id.tvClientId);
        tvStatus = (TextView) findViewById(R.id.tvStatus);

        tvSteamTemp = (TextView) findViewById(R.id.tvSteamTemp);
        tvWaterTemp = (TextView) findViewById(R.id.tvWaterTemp);
        tvWaterFlow = (TextView) findViewById(R.id.tvWaterFlow);
        tvDieselFlow = (TextView) findViewById(R.id.tvDieselFlow);
        tvManualResetLevel = (TextView) findViewById(R.id.tvManualResetLevel);
        tvWaterFeederLevel = (TextView) findViewById(R.id.tvWaterFeederLevel);
        tvAutoResetPressure = (TextView) findViewById(R.id.tvAutoResetPressure);
        tvManualResetPressure = (TextView) findViewById(R.id.tvManualResetPressure);
        tvTempLimit = (TextView) findViewById(R.id.tvTempLimit);

        btnConnect = (Button) findViewById(R.id.btnConnect);
        btnConnect.setOnClickListener(connectClick);
        btnConnect.setEnabled(false);

        btnSubscribe = (Button) findViewById(R.id.btnSubscribe);
        btnSubscribe.setOnClickListener(subscribeClick);

        btnDisconnect = (Button) findViewById(R.id.btnDisconnect);
        btnDisconnect.setOnClickListener(disconnectClick);


        /* MQTT client IDs are required to be unique per AWS IoT account.
         * This UUID is "practically unique" but does not _guarantee_
         * uniqueness.
         */

        clientId = UUID.randomUUID().toString();
        tvClientId.setText(clientId);

        // Initialize the AWS Cognito credentials provider
        // Sends info to AWS so it knows to what it needs to connect
        credentialsProvider = new CognitoCachingCredentialsProvider(
                getApplicationContext(), // context
                COGNITO_POOL_ID, // Identity Pool ID
                MY_REGION // Region
        );

        // MQTT Client
        /* Sets up the app side of being able to read and understand
         * information sent from AWS
         */
        mqttManager = new AWSIotMqttManager(clientId, CUSTOMER_SPECIFIC_ENDPOINT);

        // The following block uses a Cognito credentials provider for authentication with AWS IoT.
        new Thread(new Runnable() {
            @Override
            public void run() {
                runOnUiThread(new Runnable() {
                    @Override
                    public void run() {
                        btnConnect.setEnabled(true);
                    }
                });
            }
        }).start();
    }

这是单击连接按钮时发生的情况：

    View.OnClickListener connectClick = new View.OnClickListener() {
        @Override
        public void onClick(View v) {

            Log.d(LOG_TAG, "clientId = " + clientId);

            try {
                mqttManager.connect(credentialsProvider, new AWSIotMqttClientStatusCallback() {
                    @Override
                    public void onStatusChanged(final AWSIotMqttClientStatus status, final Throwable throwable) {
                        Log.d(LOG_TAG, "Status = " + status);

                        runOnUiThread(new Runnable() {
                            @Override
                            public void run() {
                                if (status == AWSIotMqttClientStatus.Connecting) {
                                    tvStatus.setText("Connecting...");

                                } else if (status == AWSIotMqttClientStatus.Connected) {
                                    tvStatus.setText("Connected");

                                } else if (status == AWSIotMqttClientStatus.Reconnecting) {
                                    if (throwable != null) {
                                        Log.e(LOG_TAG, "Connection error.", throwable);
                                    }
                                    tvStatus.setText("Reconnecting");
                                } else if (status == AWSIotMqttClientStatus.ConnectionLost) {
                                    if (throwable != null) {
                                        Log.e(LOG_TAG, "Connection error.", throwable);
                                        throwable.printStackTrace();
                                    }
                                    tvStatus.setText("Disconnected");
                                } else {
                                    tvStatus.setText("Disconnected");

                                }
                            }
                        });
                    }
                });
            } catch (final Exception e) {
                Log.e(LOG_TAG, "Connection error.", e);
                tvStatus.setText("Error! " + e.getMessage());
            }
        }
    };

我希望能够完全删除“连接”按钮，或者至少将其作为“重新连接”按钮。这样，当应用启动时，它已经在连接而不是等待用户输入。

Answer 1

在btnConnect.performClick()之后添加通话btnConnect.setEnabled(true);

我不知道为什么您必须在活动onCreate方法中创建新的线程，然后使用runOnUiHandle在UI线程上运行它。默认情况下，onCreate方法在UI线程上运行

Answer 2

创建一个包含connectClick内容的函数，并在onCreate中调用它。由于您没有在v中使用参数connectClick，因此该函数不需要任何参数。

在按下按钮之前如何激活按钮？

2 个答案: