Question

我正在上课的C ++项目有一些问题。我不断收到一条错误消息，指出“没有重载函数实例”。我做了一些谷歌搜索，似乎每个人都说此错误是由于将字符串传递给cin.get（）函数引起的，但是我将此函数与char而不是字符串一起使用。 Visual Studio说该错误位于：“ cin.get（nameFull）;”但我已将nameFull定义为一个字符，而不是字符串。任何帮助将不胜感激，谢谢您的时间。

    #include <iostream>
    #include <iomanip>
    using namespace std;


    int main()
    {
        const int MONTHS = 12;
        const int RETRO_MONTHS = 6;

        char nameFull[30];      // INPUT - Employee's full name
        float salaryCurrent;    // INPUT - Current annual salary
        float percentIncrease;  // INPUT - Percent increase due
        float salaryNew;        // OUTPUT - New salary after increase
        float salaryMonthly;    // OUTPUT - New monthly salary
        float retroactivePay;   // OUTPUT - Retroactive pay due employee
        int count;              // CALC - Counter for loop

        for (int count = 0; count < 3; count++) {
            cout << "What is your name?" << endl;
            cin.get(nameFull);
            cout << "What is your current salary?" << endl;
            cin >> salaryCurrent;
            cout << "What is your pay increase?" << endl;
            cin >> percentIncrease;

            salaryNew = salaryCurrent + (salaryCurrent * percentIncrease);
            salaryMonthly = salaryNew / MONTHS;
            retroactivePay = (salaryNew - salaryCurrent) * RETRO_MONTHS;

            cout << nameFull << "'s SALARY INFORMATION" << endl;

            cout << "New Salary"
                << setw(20) << "Monthly Salary"
                << setw(20) << "Retroactive Pay" << endl;

            cout << setprecision(2) << fixed << setw(10) << salaryNew
                << setw(20) << salaryMonthly
                << setw(20) << retroactivePay << endl;

            cout << "<Press enter to continue>" << endl << endl;
            cin.get();
        }
        return 0; 
}

Answer 1

nameFull是char（更具体地说是char[30]）的数组，该数组衰减为指向字符（char*）的指针。没有std::istream::get的重载，它只接受一个指向字符的指针，但有一个可以接受一个指针+您想读入的缓冲区大小。

因此，您所需要做的就是传递一个附加参数：

cin.get(nameFull, 30);

cin.get（）导致“无重载函数实例”错误

1 个答案: