我已经配置了Jwt/tymon
API身份验证并使用了自定义模型,我要的是没有JWT在登录时生成的令牌,不应访问控制器功能
路线
Route::group([
'middleware' => 'api'
// 'prefix' => 'auth'
], function ($router) {
Route::post('auth/mpalogin', 'MpaLoginController@mpaLogin')->name('login');
Route::post('auth/mpalogout', 'MpaLoginController@logout');
Route::post('auth/mparefresh', 'MpaLoginController@refresh');
Route::post('auth/mpame', 'MpaLoginController@myinfo');
Route::post('auth/mpag', 'MpaLoginController@awain');
});
CONTROLLER->最后,无需发送令牌即可访问awain
方法,这是我不希望的,我希望我在此控制器中创建的每个方法都只能由令牌访问< / strong>
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Http\Controllers\Controller;
use App\Http\Requests;
use Config;
use JWTAuth;
use JWTAuthException;
use App\Mpa;
class MpaLoginController extends Controller
{
public function __construct()
{
Config::set('jwt.user', Mpa::class);
Config::set('auth.providers', ['users' => [
'driver' => 'eloquent',
'model' => Mpa::class,
]]);
$this->middleware('auth', ['except' => ['mpaLogin']]);
}
public function mpaLogin(Request $request){
$credentials = $request->only('email', 'password');
$token = null;
try {
if (!$token = auth()->attempt($credentials)) {
return response()->json([
'response' => 'error',
'message' => 'invalid_email_or_password',
]);
}
} catch (JWTAuthException $e) {
return response()->json([
'response' => 'error',
'message' => 'failed_to_create_token',
]);
}
return response()->json([
'response' => 'success',
'result' => [
'token' => $token,
'message' => 'I am front mpa',
],
]);
}
/**
* Get the authenticated User.
*
* @return \Illuminate\Http\JsonResponse
*/
public function myinfo()
{
return response()->json(auth()->user());
}
/**
* Log the user out (Invalidate the token).
*
* @return \Illuminate\Http\JsonResponse
*/
public function logout()
{
auth()->logout();
return response()->json(['message' => 'Mpa Successfully logged out']);
}
/**
* Refresh a token.
*
* @return \Illuminate\Http\JsonResponse
*/
public function refresh()
{
return $this->respondWithToken(auth()->refresh());
}
/**
* Get the token array structure.
*
* @param string $token
*
* @return \Illuminate\Http\JsonResponse
*/
protected function respondWithToken($token)
{
return response()->json([
'access_token' => $token,
'token_type' => 'bearer',
'expires_in' => auth()->factory()->getTTL() * 60
]);
}
public function awain()
{
return response()->json("xyz");
}
}
答案 0 :(得分:1)
您可以尝试这种方式。
App\Http\Middleware
文件夹中。
文件名必须为JWTMiddleware.php
<?php
namespace App\Http\Middleware;
use Closure;
use App\Models\Authentication\Auth;
use Tymon\JWTAuth\Facades\JWTAuth;
use Tymon\JWTAuth\Exceptions\TokenExpiredException;
use Tymon\JWTAuth\Exceptions\TokenInvalidException;
use Tymon\JWTAuth\Exceptions\JWTException;
class JWTMiddleware
{
/**
* Handle an incoming request.
*
* @param \Illuminate\Http\Request $request
* @param \Closure $next
* @return mixed
*/
public function handle($request, Closure $next)
{
if (is_null($request->bearerToken())) {
return response()->json(['error' => 'Token required.'], 401);
}
try {
// attempt to verify the credentials and create a token for the user
$token = JWTAuth::getToken();
$apy = JWTAuth::getPayload($token)->toArray();
} catch (TokenExpiredException $e) {
return response()->json(['error' => 'Session Expired.', 'status_code' => 401], 401);
} catch (TokenInvalidException $e) {
return response()->json(['error' => 'Token invalid.', 'status_code' => 401], 401);
} catch (JWTException $e) {
return response()->json(['token_absent' => $e->getMessage()], 401);
}
return $next($request);
}
}
$routeMiddleware
文件的App\Http\kernel.php
中注册此中间件。protected $routeMiddleware = [
....
....
'jwt' => \App\Http\Middleware\JWTMiddleware::class,
];
Route::group(['middleware' => [ 'jwt', 'jwt.auth']], function () {
....
....
});
工作示例存储库: https://github.com/kennethtomagan/laravel-5-api-boilerplate/
答案 1 :(得分:0)
替换
C:\wherever-you-cloned-pio-repository\predictionio\docker\pio\pio_run
有了这个
$this->middleware('auth', ['except' => ['mpaLogin']]);
还要从路由组中删除中间件。在将中间件代码添加到控制器的结构中时。