Question

我有一张看起来像这样的桌子

Table: hobbies
----------------------------------------
id | name
----------------------------------------
1  | chess
2  | skydiving
________________________________________

然后每当有人注册并添加一个爱好时（为了简单起见，并确保这不是M：M，他们只能拥有一个爱好）

Table: Users
------------------
id|   name    | hobbyId
------------------
1 |Christian  | NULL

这是我的实现方式：

export async function addNewUser(userData: UserInformation): ServerReponse {
// userData = { name: "john", hobby: "skydiving" }
const hobbyRepo = getManager().getRepository('hobbies');
const hobbyId = await hobbyRepository.findOne({name: userData.hobby}) // hobbyId = { id: 2, name 'skydiving' }
const user = new User();
user.name = userData.name
user.hobby = hobbyId //user.hobby is underlined in red*
  try {
    await getManager().save(user);
  } catch(e){} //no error

我得到的user.hobby错误是Type '{}' is missing the following properties from type 'Specialty': id, name, membersts(2739)

实体：用户

@Entity('users')
export class User {

  @PrimaryGeneratedColumn()
  public id: number;

  @Column()
  public name: string;

  @ManyToOne(type => Hobby, specialty => specialty.members)
  public hobby: Hobby;
}

实体：爱好

@Entity('hobbies')
export class Hobby {
  @PrimaryGeneratedColumn()
  public id: number;

  @Column()
  public name: string;

  @OneToMany(type => User, user => user.hobby)
  public members: User[];
}

如何使用typeorm从填充的表中分配外键？谢谢您的帮助！

Answer 1

所以出现错误是因为在Hobby类中，我根据需要拥有members。无论这是不是一个好主意，我都不是100％，但是我将其设置为可选：

@OneToMany(type => User, user => user.specialy)
@JoinColomn()
public members?: User[] | User | null;

在model.ts文件中，我现在也拥有它：

const hobbyFk = await hobbyRepository.findOne({name: userData.hobby});
user.name = userData.name;
user.hobby = hobbyFk as HobbyInterface; //HobbyInterface is one I created.
with that above I was able to correctly set the fk.

希望这会在将来对其他人有所帮助。

TYPEORM将fk设置为1：m / m：1

实体：用户

实体：爱好

1 个答案: