Question

这是我尝试过的：

for i in range(len(list1)):
    if str(list2[0]) == list1[i][0]:
         list1.remove(str(list2[0]))
print(list1)

Answer 1

您并不是在内部列表上进行操作-您的外部列表不包含字符串“ apple”。您尝试从list1中删除“苹果”：

list1 = [["apple", "bd", "go", "d", "e"], ["bd", "e", "d", "go", "apple"],
         ["go", "d", "e", "bd", "apple"], ["d", "bd", "apple", "go", "e"], 
         ["e", "apple", "go", "bd", "d"]]

list2 = ["apple", "bd", "e", "d", "go"]

for i in range(len(list1)):
    if str(list2[0]) == list1[i][0]:
         list1.remove(str(list2[0]))   # list1 only contains lists, not strings
print(list1)

# iterate over all inner lists    
for inner in list1:
    # and remove "apple"
    inner.remove(list2[0]) 

print(list1)

输出：

[['bd', 'go', 'd', 'e'], ['bd', 'e', 'd', 'go'], ['go', 'd', 'e', 'bd'],
 ['d', 'bd', 'go', 'e'], ['e', 'go', 'bd', 'd']]

如果要创建一个新文件，请按照以下步骤操作：

no_apple = []

for inner in list1:
    # filter inners with list comprehension, expluce list2[0]
    no_apple.append([i for i in inner if i != list2[0]])

print(no_apple)

Answer 2

创建新列表是否受到限制？

您可以为list1内的每个列表创建一个新列表，并将它们附加到新列表中

answer = []
for inside_list in list1:
  new_inside_list = [value for value in inside_list if value not in list2]
  answer.append(new_inside_list)

这会删除出现在list1中的list2的每个元素。

请注意，new_inside_list可能会导致列表为空。只需在附加答案之前检查它是否为空

如何切换字符串

2 个答案: