我在Rosalind上遇到了一个问题,该问题涉及输出具有最高GC含量百分比和该百分比的字符串的ID,而我遇到了问题。我能够输出样本数据ID +百分比,但我不知道如何找到最高的。
#!/bin/env python3
import sys
input = input()
file = open(input, "r")
#print(input)
gc = 0
at = 0
unknown = 0
for line in file:
if line.startswith(">"):
if (gc + at) > 0:
total = gc + at
percentage = float(gc)/float(total) * 100
result = percentage
print(seq_id, result)
seq_id = line.strip()
gc = at = unknown = 0
else:
nuc_str = list(line.strip())
for n in nuc_str:
if n == "G" or n == "g" or n == "C" or n == "c":
gc += 1.0
elif n == "A" or n == "a" or n == "T" or n == "t":
at += 1.0
else:
unknown += 1.0
total = gc + at
percentage = float(gc)/float(total) * 100
result = percentage
print(seq_id, result)
所需的输出是:
Rosalind_0808
60.919540
我得到的输出是:
>Rosalind_6404 53.75
>Rosalind_5959 53.57142857142857
>Rosalind_0808 60.91954022988506
输入文件是取自rosalind的样本数据fasta文件:
>Rosalind_6404
CCTGCGGAAGATCGGCACTAGAATAGCCAGAACCGTTTCTCTGAGGCTTCCGGCCTTCCCTCCCACTAATAATTCTGAGG
>Rosalind_5959
CCATCGGTAGCGCATCCTTAGTCCAATTAAGTCCCTATCCAGGCGCTCCGCCGAAGGTCTATATCCATTTGTCAGCAGACACGC
>Rosalind_0808
CCACCCTCGTGGTATGGCTAGGCATTCAGGAACCGGAGAACGCTTCAGACCAGCCCGGACTGGGAACCTGCGGGCAGTAGGTGGAAT
我正在尝试不使用biopython。
答案 0 :(得分:0)
可以使用一些优化来使您的代码更好,更简洁。例如,使用list
中的tuples
,可以使序列标头与其GC内容相关联。
所以您的循环看起来像:
# Create an empty list to collect results
results = []
for line in file:
if line.startswith(">"):
if (gc + at) > 0:
total = gc + at
percentage = float(gc)/float(total) * 100
result = percentage
# Add results to the list here
results.append((seq_id, result))
seq_id = line.strip()
gc = at = unknown = 0
else:
nuc_str = list(line.strip())
for n in nuc_str:
if n == "G" or n == "g" or n == "C" or n == "c":
gc += 1.0
elif n == "A" or n == "a" or n == "T" or n == "t":
at += 1.0
else:
unknown += 1.0
运行循环后,results
如下:
[
("Rosalind_6404", 53.75),
("Rosalind_5959", 53.57142857142857),
("Rosalind_0808", 60.91954022988506),
]
然后,要收集具有最高GC含量的序列,我们可以使用itemgetter
:
from operator import itemgetter
result = max(results, key=itemgetter(1))
我们使用key
参数告诉max
在元组中找到位置1
处具有最高值的列表项。
result
看起来像这样:
("Rosalind_0808", 60.91954022988506)
要以所需格式输出结果,我们可以使用format
:
print("{}\n{:.6f}".format(*result))
哪个输出:
Rosalind_0808
60.919540
其他优化:
with
语句打开文件,这样做的好处是在处理后可以正确关闭文件len
)作为除数lower()
而不是比较大写和小写我写了自己的版本,看起来像这样:
from operator import itemgetter
res = []
with open("test.fa", "r") as fh:
for line in fh:
line = line.strip()
if line[0] in ">":
header = line[1:]
seq = next(fh).strip()
gc = sum(1 for base in seq if base.lower() in "gc")
res.append((header, gc / len(seq) * 100))
result = max(res, key=itemgetter(1))
print("{}\n{:.6f}".format(*result))