我需要对销售数据库中的每个“产品”对象进行汇总,并对“价格”和“数量”求和,以进行产品分类。
我能够按“产品”分组,但是我无法将每个对象的价格和数量求和。
{$group: {
_id: '$products.items',
totalprice:{$sum: "$products.items.price"},
}}
下面的销售数据库样本中,我需要返回为每个“产品”出售的“价格”和“数量”字段的总和。
{
"_id": {
"$oid": "5d753707c0cd851e80da914c"
},
"created_on": {
"$date": {
"$numberLong": "1567962886000"
}
},
"custumer": {
"name": "Teste",
"cep": "teste",
"address": "teste",
"district": "test",
"city": "test",
"numb": "50",
"comple": "test",
"state": "test",
"cpf": "test",
"birth": "30/09/1977",
"email": "test@gmail.com",
"phone": {
"$numberDouble": "1111111111111"
},
"gender": "M",
"portalt": {
"status": "true",
"vendor": "test",
"phone": {
"$numberDouble": "11111111111"
},
"sim": "011111111111",
"salesnumb": "1222222222222222222"
}
},
"payment": {
"method": "Boleto",
"type": "Parcelado",
"installments": "5",
"billing_date": "15"
},
**"products": {
"items": {
"5d515979736802000415a561": {
"item": {
"_id": "5d515979736802000415a561",
"name_produto": "Product 1",
"resumo": "Minutos ilimitados,20GB + 2GB",
"price": "110",
"_image": "images/test.jpg"
},
"quantity": {
"$numberInt": "2"
},
"price": {
"$numberInt": "220"
}
},
"5d515aba736802000415a562": {
"item": {
"_id": "5d515aba736802000415a562",
"name_produto": "Product 2",
"resumo": "Minutos ilimitados,3GB + 1GB",
"price": "80",
"_image": "images/test.jpg"
},
"quantity": {
"$numberInt": "1"
},
"price": {
"$numberInt": "80"
}
},
"5d515dbf736802000415a564": {
"item": {
"_id": "5d515dbf736802000415a564",
"name_produto": "Product 3",
"resumo": "Minutos ilimitados,30GB + 3GB",
"price": "150",
"_image": "images/test.jpg"
},
"quantity": {
"$numberInt": "1"
},
"price": {
"$numberInt": "150"
}
}
},**
"totalItems": {
"$numberInt": "4"
},
"totalPrice": {
"$numberInt": "450"
}
},
"seller": {
"_id": {
"$oid": "5cd086787dc59921bcad94d8"
},
"name": "test"
}
}
我需要输出如下内容:
_id:Object
5d515979736802000415a561:{sum_price: 300, sum_quantity: 30 }
5d515aba736802000415a562:{sum_price: 500, sum_quantity: 60 }
5d515dbf736802000415a564:{sum_price: 600, sum_quantity: 70 }
非常感谢!
答案 0 :(得分:0)
因此,让我们与OP一起对各个产品的价格和数量求和。除去与询问无关的其他字段,我们得出这样的结果:
var r =
[
{
_id:0,
"products": {
"items": {
"5d515979736802000415a561": {
"quantity": 2,
"price": 220,
},
"5d515aba736802000415a562": {
"quantity": 1,
"price": 80
}
}
}
}
, {
_id:1,
"products": {
"items": {
"5d515979736802000415a561": { // deliberately same id as doc above but different quantity and price
"quantity": 3,
"price": 330
},
"5d515aba736802000415a562": { // same
"quantity": 2,
"price": 160
},
"5d515979736802000415ZZZZ": { // different than above; adds "third item"
"quantity": 4,
"price": 200
}
}
}
}
];
请注意,整个item
内部字段基本上并不重要,至少其中一个字段仅包含单价,而不包含总价格(数量)和每种产品的数量。
"5d515dbf736802000415a564": {
"item": {
"_id": "5d515dbf736802000415a564",
// etc
因此,现在我们使用$objectToArray
将密钥转换为rval。这为我们提供了$group
可以使用的功能,因此这里是一个解决方案:
db.foo.aggregate([
{$project: {X: {$objectToArray: "$products.items"}}}
,{$unwind: "$X"}
,{$group: {_id: "$X.k", tot_q: {$sum:"$X.v.quantity"}, tot_amt: {$sum:"$X.v.price"}} }
]);
上面给出的输入产生了:
{ "_id" : "5d515979736802000415ZZZZ", "tot_q" : 4, "tot_amt" : 200 }
{ "_id" : "5d515aba736802000415a562", "tot_q" : 3, "tot_amt" : 240 }
{ "_id" : "5d515979736802000415a561", "tot_q" : 5, "tot_amt" : 550 }