我试图仅在单击时打开元素,但每次单击时才关闭元素,即使打开一次弹出窗口后,关闭函数( ClickedOut(event))也会触发元素已经关闭。
单击弹出框将打开的任何框,然后在弹出框关闭的任何位置单击,而目标是在单击框时打开弹出框,仅当在弹出框之外单击弹出框时,才应将其关闭。
https://stackblitz.com/edit/angular-7edvms?file=src/app/app.component.ts
<div (click)="ClickedOut($event)">
<div class="box1" (mouseenter)="addClickEvent($event)"
(mouseleave)="addClickEvent($event)" (click)="addClickEvent($event)">
On click
</div>
<div class="box2" (mouseenter)="addClickEvent($event)"
(mouseleave)="addClickEvent($event)" (click)="addClickEvent($event)">
On click
</div>
<fs-modal *ngIf="opened" [ngStyle]="modalStyleClikedFlag ? modelClickedStyle
:modelStyle" (mouseleave)="onPopEvent($event)">
</fs-modal>
</div>
TS文件
export class AppComponent {
modelStyle: any = {
display: 'none'
};
modelClickedStyle: any = {
display: 'none'
};
modalStyleClikedFlag;
opened;
addClickEvent(e) {
let x = e.currentTarget.getBoundingClientRect();
if (e.type === 'click') {
this.modalStyleClikedFlag = true;
this.modelClickedStyle = {
top: 0 + 'px',
left: 0 + 'px',
height: 900 + 'px',
width: 90 + '%',
display: 'block'
};
this.opened = false;
}
else if (e.type === 'mouseenter') {
this.opened = true;
this.modalStyleClikedFlag = false;
if(((window.innerWidth || document.documentElement.clientWidth) -
x.right) >200 ){
this.modelStyle = {
top: 0 + 'px',
left: x.right + 'px',
height: screen.height + 'px',
width: 65 +'%',
display: 'flex'
};
}else{
this.modelStyle = {
top: 0 + 'px',
right : ((window.innerWidth||document.documentElement.clientWidth)
- x.left)
+ 'px',
height: screen.height + 'px',
width: 65 +'%',
display: 'flex'
};
}
}
else if (e.type === 'mouseleave' && e.clientX < x.right) {
this.modelStyle = {
display: 'none'
};
}
}
onPopEvent() {
this.modelStyle = {
display: 'none'
};
}
ClickedOut(event): void {
event.preventDefault();
this.opened = !this.opened
}
}
答案 0 :(得分:1)
这是因为孩子总是会从父母那里得到click事件:这被称为事件冒泡,您可以找到几种在线停止事件的方法。
您可以采取哪些预防措施:
<fs-modal *ngIf="opened" (click)="$event.stopPropagation()" ... >