Question

表数据如下，需要提取满足以下条件的记录

这里的值= Value2-Value1

    Value of two days back data should be > 2
    Value of last day  data is < 0
    Value of next day data is < 4 and >0
    Value of after next day data > 4

所有日期均为工作日，如果任何日期为星期五，则需要与第二天（即星期一）进行比较。比较只能在其他日子进行

必须在下面的输出中。

1         4-1-2018   15          18
2         3-1-2018    3           0 


    -----------------------------------
    code      Date      Value1      Value2
    ---------------------------------------
    1         1-1-2018   13          14
    1         2-1-2018   14          18
    1         3-1-2018   15          11
    1         4-1-2018   15          18
    1         5-1-2018   15          18
    1         6-1-2018   11          18
    1         7-1-2018   15          18
    2         1-1-2019    1           3
    2         2-1-2018    2           5
    2         3-1-2018    3           0
    2         4-1-2018    3           7
    2         5-1-2018    3           4
    2         6-1-2018    3           9
    2         7-1-2018    3           7

在比较多个行时，我非常困惑，非常感谢您的帮助。

Answer 1

从v2012开始，我们有了support for LAG() and LEAD()。试试看：

SET DATEFORMAT dmy;

DECLARE @tbl TABLE(code INT,[Date] DATE,Value1 INT,Value2 INT);
INSERT INTO @tbl VALUES
 (1,'1-1-2018',13,14)
,(1,'2-1-2018',14,18)
,(1,'3-1-2018',15,11)
,(1,'4-1-2018',15,18)
,(1,'5-1-2018',15,18)
,(1,'6-1-2018',11,18)
,(1,'7-1-2018',15,18)
,(2,'1-1-2019', 1, 3)
,(2,'2-1-2018', 2, 5)
,(2,'3-1-2018', 3, 0)
,(2,'4-1-2018', 3, 7)
,(2,'5-1-2018', 3, 4)
,(2,'6-1-2018', 3, 9)
,(2,'7-1-2018', 3, 7);


WITH cte AS
(
    SELECT *
          ,LAG(Value2-Value1,2) OVER(PARTITION BY code ORDER BY [Date]) TwoDaysBack
          ,LAG(Value2-Value1,1) OVER(PARTITION BY code ORDER BY [Date]) Yesterday
          ,LEAD(Value2-Value1,1) OVER(PARTITION BY code ORDER BY [Date]) tomorrow
          ,LEAD(Value2-Value1,2) OVER(PARTITION BY code ORDER BY [Date]) TwoDaysAhead
    FROM @tbl 
)
SELECT *
FROM cte;

我不太了解如何在过滤器中使用这些值来获得预期的输出。如果您需要帮助，请回来...

结果

+------+------------+--------+--------+-------------+-----------+----------+--------------+
| code | Date       | Value1 | Value2 | TwoDaysBack | Yesterday | tomorrow | TwoDaysAhead |
+------+------------+--------+--------+-------------+-----------+----------+--------------+
| 1    | 2018-01-01 | 13     | 14     | NULL        | NULL      | 4        | -4           |
+------+------------+--------+--------+-------------+-----------+----------+--------------+
| 1    | 2018-01-02 | 14     | 18     | NULL        | 1         | -4       | 3            |
+------+------------+--------+--------+-------------+-----------+----------+--------------+
| 1    | 2018-01-03 | 15     | 11     | 1           | 4         | 3        | 3            |
+------+------------+--------+--------+-------------+-----------+----------+--------------+
| 1    | 2018-01-04 | 15     | 18     | 4           | -4        | 3        | 7            |
+------+------------+--------+--------+-------------+-----------+----------+--------------+
| 1    | 2018-01-05 | 15     | 18     | -4          | 3         | 7        | 3            |
+------+------------+--------+--------+-------------+-----------+----------+--------------+
| 1    | 2018-01-06 | 11     | 18     | 3           | 3         | 3        | NULL         |
+------+------------+--------+--------+-------------+-----------+----------+--------------+
| 1    | 2018-01-07 | 15     | 18     | 3           | 7         | NULL     | NULL         |
+------+------------+--------+--------+-------------+-----------+----------+--------------+
| 2    | 2018-01-02 | 2      | 5      | NULL        | NULL      | -3       | 4            |
+------+------------+--------+--------+-------------+-----------+----------+--------------+
| 2    | 2018-01-03 | 3      | 0      | NULL        | 3         | 4        | 1            |
+------+------------+--------+--------+-------------+-----------+----------+--------------+
| 2    | 2018-01-04 | 3      | 7      | 3           | -3        | 1        | 6            |
+------+------------+--------+--------+-------------+-----------+----------+--------------+
| 2    | 2018-01-05 | 3      | 4      | -3          | 4         | 6        | 4            |
+------+------------+--------+--------+-------------+-----------+----------+--------------+
| 2    | 2018-01-06 | 3      | 9      | 4           | 1         | 4        | 2            |
+------+------------+--------+--------+-------------+-----------+----------+--------------+
| 2    | 2018-01-07 | 3      | 7      | 1           | 6         | 2        | NULL         |
+------+------------+--------+--------+-------------+-----------+----------+--------------+
| 2    | 2019-01-01 | 1      | 3      | 6           | 4         | NULL     | NULL         |
+------+------------+--------+--------+-------------+-----------+----------+--------------+

简而言之：

LAG（）和LEAD（）都使用所需值的参数，第二个参数是我们要跳过的行数，第三个参数是您可以指定的默认值，以避免在结果中出现NULL范围内没有行。

如果我们想将集合分为组和排序顺序，则OVER（）子句会告诉任何 windowing函数（否则，系统将不知道什么是 leading < / em>或滞后。

Answer 2

具有lead和lag窗口功能：

with cte as (
  select *,
    lag(value2 - value1, 2) over (partition by code order by date) prev2,
    lag(value2 - value1, 1) over (partition by code order by date) prev1,
    lead(value2 - value1, 1) over (partition by code order by date) next1,
    lead(value2 - value1, 2) over (partition by code order by date) next2
  from tablename
)
select code, date, value1, value2
from cte 
where prev2 > 2 and prev1 < 0 and next1 > 0 and next1 < 4 and next2 > 4

请参见demo。
结果：

code | date                | value1 | value2
---: | :------------------ | -----: | -----:
   1 | 01/04/2018 00:00:00 |     15 |     18
   2 | 01/04/2018 00:00:00 |      3 |      7

您对code = 2的预期结果与我的结果之间存在差异，因此请检查其有效性。

通过比较4个不同的行来提取数据

2 个答案: