Question

我是OOP的新手，我一直在研究这个例子，但我似乎无法摆脱这个错误

Parse error: syntax error, unexpected ';', expecting T_FUNCTION in C:\Program Files (x86)\Apache Software Foundation\Apache2.2\...\php_late_static_bindings.php on line 16

我试图执行以下代码：

abstract class father {
    protected $lastname="";
    protected $gender="";

    function __construct($sLastName){
        $this->lastname = $sLastName;
    }

    abstract function getFullName();

    public static function create($sFirstName,$sLastName){
        return new self($sFirstName,$sLastName);
    };
}

class boy extends father{
    protected $firstname="";

    function __construct($sFirstName,$sLastName){
        parent::__construct($sLastName);
        $this->firstname = $sFirstName;
    }

    function getFullName(){
        return("Mr. ".$this->firstname." ".$this->lastname."<br />");
    }
}

class girl extends father{
    protected $firstname="";

    function __construct($sFirstName,$sLastName){
        parent::__construct($sLastName);
        $this->firstname = $sFirstName;
    }

    function getFullName(){
        return("Ms. ".$this->firstname." ".$this->lastname."<br />");
    }

}


$oBoy = boy::create("John", "Doe");
print($oBoy->getFullName());

有没有人有任何想法？ $ oGirl = girl :: create（“Jane”，“Doe”）; 打印（$ oGirl-＆GT; getFullName（））;

Answer 1

首先必须删除方法定义后的分号：

public static function create($sFirstName,$sLastName){
    return new self($sFirstName,$sLastName);
} // there was a semi-colon, here

然后，您可能希望使用static，而不是self ，此处：

public static function create($sFirstName,$sLastName){
    return new static($sFirstName,$sLastName);
}

说明：

self指向编写它的类 - 这里是father类，它是抽象的，不能实例化。
static表示后期静态绑定 - 并且，此处将指向您的boy类;这是你想要实现的那个。

Answer 2

PHP的错误报告通常非常好。只需阅读错误。问题出在这里：

public static function create($sFirstName,$sLastName){
    return new self($sFirstName,$sLastName);
};

删除训练分号。

public static function create($sFirstName,$sLastName){
    return new self($sFirstName,$sLastName);
}

php后期静态绑定修复错误期待T_FUNCTION

2 个答案: