在我的PHP代码中,我请求获取html中下拉菜单的数据。在pgAdmin中,我尝试这样做:
select distinct annee + 1 as annee from revisionrdt.rdt;
在PHP中:
$data = DB::table('previsionrdt.rdt')
->select ('annee')
->distinct ('annee + 1 as annee')
->from ('previsionrdt.rdt')
->get();
通常此请求返回“ 2019”,但在PHP中,该请求返回“ 2018”给我。
答案 0 :(得分:1)
您的代码会生成另一个查询:
DB::table('previsionrdt.rdt')
->select ('annee')
->distinct ('annee + 1 as annee')
->from ('previsionrdt.rdt')
->get();
->
select distinct `annee` from `previsionrdt`.`rdt`
应该是这样的:
DB::table('previsionrdt.rdt')
->select(DB::raw('distinct annee + 1 as annee'))
->get();
->
select distinct annee + 1 as annee from `previsionrdt`.`rdt`
您可以使用dump()
或dd()
(转储并消亡)代替get()
来打印和调试查询。