Admin route.ts with child
const AdminRoutes: Routes = [{
path: '', component: AdminComponent, children: [
{ path: 'dashboard', component: DashboardComponent },
{ path: 'adduser', component: AdduserComponent }, { path: 'userlist', component: UserlistComponent }, { path: 'userdetails', component: UserdetailsComponent }, { path: 'appliedleaves', component: LeavesAppliedComponent },
{ path: '', redirectTo: 'dashboard', pathMatch:'full' }]
}]
app-routing.ts
const routes: Routes = [
{ path: 'register', component: RegisterComponent },
{ path: 'login', component: LoginComponent },
{ path: 'employee', loadChildren: './employee/employee.module#EmployeeModule', canActivate: [authguardModule] },
{ path: 'admin', loadChildren: './admin/admin.module#AdminModule', canActivate: [authguardModule] }
];
我有一个管理模块。它有3个子级:仪表板,用户列表,叶子。导航到admin / userlist时,我需要显示userlist,对于所有其他用户,也是如此。 但这仅在我导航至仪表板或离开时显示用户列表。
如何使用* ngIf实现呢?喜欢:
<app-userdetails *ngIf="something here?"></app-userdetails>
答案 0 :(得分:1)
这种情况可以在路由器模块中实现,您将在routes数组中执行以下操作:
[
{ path: 'userlist', component: your userlist component classname, for ex:
UserListComponent },
{ path: 'dashboard', component: your dashboard component classname },
{ path: 'leaves', component: your leaves component classname }
]
答案 1 :(得分:0)
对adminroute使用以下路由:
const adminRoute : Routes = [
path : '',
component : adminRoute,
childrean :[
{route of leaves }
]
]