我正在Spring数据Jpa中使用OneToMany关系,并使用postMan测试api
@Entity
@Table(name = "book_category")
public class BookCategory {
ParentEntity
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "bookCat_id")
private Long id;
private String name;
@OneToMany(cascade = CascadeType.ALL, mappedBy="bookCategory")
private Set<Book> books;
public BookCategory(String name, Set<Book> books) {
this.name = name;
this.books = books;
}
// getter and setter
}
ChildEntity
@Entity
@Table(name = "book")
public class Book {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "book_id")
private Long bookId;
private String name;
@ManyToOne(cascade = CascadeType.PERSIST)
@JoinColumn(name = "bookCat_id")
BookCategory bookCategory;
public Book() {
}
//getter and Setter
}
ControllerClass
@RestController
@RequestMapping(value = "/bookCategory")
public class BookController {
@Autowired
BookCategoryRepository bookCategoryRepository;
@Autowired
BookRepository bookRepository;
@PostMapping("/addBookCategory")
public BookCategory savePerson(@Valid @RequestBody BookCategory bookCategory){
return bookCategoryRepository.save(bookCategory);
}
}
从邮递员处调用Rest Api并将json传递为
{
"name":"Category 1",
"books":[
{"name" : "Hello Koding 1"},
{"name":"Hello Koding 2"}
]
}
以下查询由休眠查询执行也是正确的,而我正在调用休息点的东西 休眠:插入book_category(name)值(?) 休眠:将值(?,?)插入书(book_cat_id,name)
它没有插入book_cat_id,在book_cat_id中它传递了null,因此null被存储了
数据库中存储的数据 book_category Parent Table in database
book(ChildTable) book(ChildTable) 我想得到像儿童桌子 I want my table like this
答案 0 :(得分:3)
问题是您没有在子对象中设置父对象。您应该在代码中的某个位置调用
public void setBookCategory(BookCategory bookCategory) { ... }
Book实体的方法。
我建议通过在控制器中使用DTO并将其映射到服务层中的实体来解决此问题,因为使用持久性实体作为http请求的参数会导致严重的安全漏洞,如here所述。
编辑:另外,甚至以为我不鼓励这种解决方案是像这样修改savePerson方法
@PostMapping("/addBookCategory")
public BookCategory savePerson(@Valid @RequestBody BookCategory bookCategory){
bookCategory.getBooks().forEach(book -> book.setBookCategory(bookCategory));
return bookCategoryRepository.save(bookCategory);
}