如何解决JavaScript函数中的导入错误

时间:2019-09-01 12:19:16

标签: javascript python execjs

我有以下js代码:

function getSlideAnswer(responseId, fpToken, coordinateX, traceData) {

    coordinateX = Math.floor(coordinateX);
    var encryptData = {
        "track": traceData,
        "x": coordinateX + "",
        "p": "0,0",
        "finger": fpToken
    };
    var t = CryptoJS.enc.Utf8.parse(responseId.substr(0, 16));
    return CryptoJS.AES.encrypt(JSON.stringify(encryptData), t, {
        iv: t,
        mode: CryptoJS.mode.CBC,
        padding: CryptoJS.pad.Pkcs7
    }).ciphertext.toString().toUpperCase();
}

但是,我收到以下错误:

execjs._exceptions.ProgramError: TypeError: 'JSON' is undefined

如何解决错误?

1 个答案:

答案 0 :(得分:0)

您可以在JS或Python中将strigify替换为字符串连接。
不确定参数类型,但不确定JS中的示例:

function getSlideAnswer(responseId, fpToken, coordinateX, traceData) {

    coordinateX = Math.floor(coordinateX);
    var encryptData = '{"track":"' + traceData +
        '","x":"' + coordinateX +
        '","p":"0,0","finger":"' + fpToken +
    '"}';
    var t = CryptoJS.enc.Utf8.parse(responseId.substr(0, 16));
    return CryptoJS.AES.encrypt(encryptData, t, {
        iv: t,
        mode: CryptoJS.mode.CBC,
        padding: CryptoJS.pad.Pkcs7
    }).ciphertext.toString().toUpperCase();
}
Test()

function Test() {
    var traceData="foo", coordinateX = 123, fpToken = "bar";
    var encryptData = {
        "track": traceData,
        "x": coordinateX + "",
        "p": "0,0",
        "finger": fpToken
    };
    console.log(JSON.stringify(encryptData));
    var encryptDataStrigified = '{"track":"' + traceData +
        '","x":"' + coordinateX +
        '","p":"0,0","finger":"' + fpToken +
    '"}';
    console.log(encryptDataStrigified);
    console.log(JSON.stringify(encryptData) == encryptDataStrigified);
}