我有关于产品的数据,其中有一些字段(String url = "http://www.yourdomain/loginstudent.php";
RequestParams params = new RequestParams();
params.put("username", YOURTEXT);
params.put("password", lng);
AsyncHttpClient client=new AsyncHttpClient();
client.post(url, params, new TextHttpResponseHandler() {
@Override
public void onFailure(int statusCode, Header[] headers, String responseString, Throwable throwable) {
Log.d(TAG, "onFailure:CrachReporter " + throwable.toString());
}
@Override
public void onSuccess(int statusCode, Header[] headers, String responseString) {
}
});
...)。它已在Elastic Search中建立了索引。而且我想在Shop中搜索产品的maxProductVersion。
例如:
_id, Shop, ProductVerion
版本可能相同。
现在,我要获得的产品具有:
Shop Amazon has 3 Version crawl product: 111,222,333.
Shop Ebay has 2 version: 222,444
Shop Alibaba has 2 version: 111, 444
但我不知道对此进行查询。 请帮帮我!
答案 0 :(得分:1)
我尝试了一些示例文档。我将版本字段保留为数字字段。
这些是我尝试过的示例文档
[
{
"_index": "test",
"_type": "doc",
"_id": "12334",
"_score": 1,
"_source": {
"shopName": "amazon",
"version": 341
}
},
{
"_index": "test",
"_type": "doc",
"_id": "123",
"_score": 1,
"_source": {
"shopName": "amazon",
"version": 3412
}
},
{
"_index": "test",
"_type": "doc",
"_id": "1233",
"_score": 1,
"_source": {
"shopName": "amazon",
"version": 341
}
},
{
"_index": "test",
"_type": "doc",
"_id": "1238",
"_score": 1,
"_source": {
"shopName": "alibaba",
"version": 34120
}
},
{
"_index": "test",
"_type": "doc",
"_id": "1239",
"_score": 1,
"_source": {
"shopName": "alibaba",
"version": 3414
}
},
{
"_index": "test",
"_type": "doc",
"_id": "123910",
"_score": 1,
"_source": {
"shopName": "alibaba",
"version": 124
}
}
]
按照@demas的指定,我继续进行术语汇总和热门歌曲汇总
indexName/_search
{
"size": 0,
"aggs": {
"shop": {
"terms": {
"field": "shopName.keyword"
},
"aggs": {
"product": {
"top_hits": {
"size": 1,
"sort": [
{
"version": {
"order": "desc"
}
}
]
}
}
}
}
}
}
这应该为您提供包含每个商店的最高产品版本号的文档,如下所示。
{
"took": 8,
"timed_out": false,
"_shards": {
"total": 5,
"successful": 5,
"skipped": 0,
"failed": 0
},
"hits": {
"total": 6,
"max_score": 0,
"hits": []
},
"aggregations": {
"shop": {
"doc_count_error_upper_bound": 0,
"sum_other_doc_count": 0,
"buckets": [
{
"key": "alibaba",
"doc_count": 3,
"product": {
"hits": {
"total": 3,
"max_score": null,
"hits": [
{
"_index": "test",
"_type": "doc",
"_id": "1238",
"_score": null,
"_source": {
"shopName": "alibaba",
"version": 34120
},
"sort": [
34120
]
}
]
}
}
},
{
"key": "amazon",
"doc_count": 3,
"product": {
"hits": {
"total": 3,
"max_score": null,
"hits": [
{
"_index": "test",
"_type": "doc",
"_id": "123",
"_score": null,
"_source": {
"shopName": "amazon",
"version": 3412
},
"sort": [
3412
]
}
]
}
}
}
]
}
}
}
答案 1 :(得分:0)
如果提供可重现的示例会更好,但是看起来您需要使用aggregation framework:term aggregation和top hits aggregation:
GET /_search
{
"aggs": {
"shops": {
"terms": { "field": "Shop" }
},
"aggs": {
"tops": {
"top_hits": {
"size": 100
}
}
}
}
}