我试图向该基本罗马数字计算器添加一个类,但是当我尝试从该类运行该函数时,出现了NameError。我不确定发生了什么。
我试图更改代码的顺序,但别无其他,因为我不知道错误的原因是什么。
此外,我不知道为什么,但是我无法将类(下面)放入代码块中。
class Roman_Number():
roman_numeral_table = [
("M", 1000), ("CM", 900), ("D", 500),
("CD", 400), ("C", 100), ("XC", 90),
("L", 50), ("XL", 40), ("X", 10),
("IX", 9), ("V", 5), ("IV", 4),
("I", 1)
]
r = input('If you want to go from Roman to Number, enter "1." If you want to go from Number to Roman, enter "2"')
if r == 1:
roman_to_int()
else:
int_to_roman()
def int_to_roman():
number = int(input('Provide Number: '))
if number < 1 or number > 3999:
print('Number must be inbetween 1 and 3999')
else:
print('Valid Number')
roman_numerals = []
for numeral, value in roman_numeral_table:
while value <= number:
number -= value
roman_numerals.append(numeral)
print(''.join(roman_numerals))
def roman_to_int():
pass
我希望它开始运行int_to roman(),但我只是遇到错误。
我更改了顺序,现在得到的是“ roman_numeral_table未定义”。为什么以及如何解决此问题?
答案 0 :(得分:1)
您将收到此错误,因为python按语法顺序执行它块,因此您需要先定义一个函数,然后才能对其进行调用/引用。试试这个:
def roman_to_int():
pass
def int_to_roman():
number = int(input('Provide Number: '))
if number < 1 or number > 3999:
print('Number must be inbetween 1 and 3999')
else:
print('Valid Number')
class Roman_Number():
roman_numeral_table = [
("M", 1000), ("CM", 900), ("D", 500),
("CD", 400), ("C", 100), ("XC", 90),
("L", 50), ("XL", 40), ("X", 10),
("IX", 9), ("V", 5), ("IV", 4),
("I", 1)
]
r = input('If you want to go from Roman to Number, enter "1." If you want to go from Number to Roman, enter "2"')
if r == 1:
roman_to_int()
else:
int_to_roman()
roman_numerals = []
for numeral, value in roman_numeral_table:
while value <= number:
number -= value
roman_numerals.append(numeral)
print(''.join(roman_numerals))
答案 1 :(得分:0)
Python是一种解释语言。因此,需要在首次调用之前定义函数。只需将def int_to_roman():
块移动到roman_numeral_table定义的正下方,代码就可以正常工作。
赞:
class Roman_Number():
roman_numeral_table = [
("M", 1000), ("CM", 900), ("D", 500),
("CD", 400), ("C", 100), ("XC", 90),
("L", 50), ("XL", 40), ("X", 10),
("IX", 9), ("V", 5), ("IV", 4),
("I", 1)
]
def int_to_roman():
number = int(input('Provide Number: '))
if number < 1 or number > 3999:
print('Number must be inbetween 1 and 3999')
else:
print('Valid Number')
roman_numerals = []
for numeral, value in roman_numeral_table:
while value <= number:
number -= value
roman_numerals.append(numeral)
print(''.join(roman_numerals))
def roman_to_int():
pass
r = input('If you want to go from Roman to Number, enter "1." If you want to go from Number to Roman, enter "2"')
if r == 1:
roman_to_int()
else:
int_to_roman()
答案 2 :(得分:0)
将您的代码更改为类似的名称即可。 Python要求您在调用函数之前先定义一个函数。
class Roman_Number():
roman_numeral_table = [
("M", 1000), ("CM", 900), ("D", 500),
("CD", 400), ("C", 100), ("XC", 90),
("L", 50), ("XL", 40), ("X", 10),
("IX", 9), ("V", 5), ("IV", 4),
("I", 1)
]
r = input('If you want to go from Roman to Number, enter "1." If you want to go from Number to Roman, enter "2"')
def int_to_roman():
number = int(input('Provide Number: '))
if number < 1 or number > 3999:
print('Number must be inbetween 1 and 3999')
else:
print('Valid Number')
roman_numerals = []
for numeral, value in roman_numeral_table:
while value <= number:
number -= value
roman_numerals.append(numeral)
print(''.join(roman_numerals))
def roman_to_int():
pass
if r == 1:
roman_to_int()
else:
int_to_roman()