我有以get变量形式获取值的代码。问题是我现在想将变量放入div(用于datetimepicker)。当我这样说时,该变量未传递。任何帮助将不胜感激。我当前的代码如下:
工作变量:
Start Date: <input type="text" class="date-time-input" name="sdate" id="sdatefield"/><br/>
在div中不起作用的变量:
Start Date: <div class="container">
<div class="row">
<div class='col-sm-6'>
<div class="form-group">
<div class='input-group date' name="sdate" id='sdatefield'>
<input type='text' class="form-control" />
<span class="input-group-addon">
<span class="glyphicon glyphicon-calendar"></span>
</span>
</div>
</div>
</div>
<script type="text/javascript">
$(function () {
$('#sdatefield').datetimepicker({
sideBySide: true,
format: 'DD-MM-YYYY HH:mm:ss',
});
});
</script>
</div>
</div>
答案 0 :(得分:1)
发现您将id="sdatefield"
添加到了<div id="sdatefield">
而非<input id="sdatefield">
上,这导致了此问题,因为您将datetimepicker绑定到了此输入字段。
尝试以下方法
$(function () {
$('#sdatefield').datetimepicker({
sideBySide: true,
format: 'DD-MM-YYYY HH:mm:ss',
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery-datetimepicker/2.5.20/jquery.datetimepicker.js"> </script>
Start Date: <div class="container">
<div class="row">
<div class='col-sm-6'>
<div class="form-group">
<div class='input-group date' name="sdate" >
<input type='text' class="form-control" id="sdatefield"/>
<span class="input-group-addon">
<span class="glyphicon glyphicon-calendar"></span>
</span>
</div>
</div>
</div>
<script type="text/javascript">
</script>
</div>
</div>
谢谢