Question

考虑下面的表格，我正在做行数据乘法：

with v1 (member_id, the_number) as 
(
select 1, 3 from dual union all
select 1, 5 from dual union all
select 2, 2 from dual union all
select 2, 3 from dual union all
select 2, 4 from dual union all
select 3, 9 from dual union all
select 3, 3 from dual union all
select 3, 2 from dual
)
select member_id, EXP(SUM(LN(the_number))) from v1
GROUP BY member_id;

它给出的正确结果为：

MEMBER_ID   EXP(SUM(LN(THE_NUMBER)))
1           15
2           24
3           54

当我在the_number列中输入负值时，出现以下Oracle错误：ORA-01428: argument 'x' is out of range这是因为LN ()参数的范围> 0。

如何修改查询，以便在the_number列中也可以具有负值？我正在使用Oracle 11g。

Answer 1

获取数字绝对值的乘积，最后乘以-1或1，具体取决于是否存在奇数或偶数的负数字：< / p>

select 
  member_id,
  CASE WHEN MOD(SUM(CASE WHEN the_number < 0 THEN 1 ELSE 0 END), 2) = 1 THEN -1 ELSE 1 END *
  EXP(SUM(LN(ABS(the_number)))) from v1
GROUP BY member_id;

请参见demo。

Oracle中的行数据乘法

1 个答案: