使用WCF Restful服务将图像上载到数据库

时间:2011-04-23 14:37:35

标签: iphone file-upload wcf-rest

我正在使用WCF restful服务将图像上传到我的数据库 代码:

[OperationContract]
        [WebInvoke(Method = "POST", UriTemplate = "AddDealImage/{id}")]
        long AddDealImage(string id, Stream image);

public long AddDealImage(string id, Stream image)
        {
            //add convert Stram to byte[]
            byte[] buffer = UploadFile.StreamToByte(image);
            //create image record for database
            Img img = ImgService.NewImage(DateTime.Now.ToFileTime().ToString(), "", buffer, "image/png");
            ImgService.AddImage(img);
            //return image id
            return img.ImageId;
        }

public static byte[] StreamToByte(Stream stream)
        {
            byte[] buffer = new byte[16 * 1024];
            using (MemoryStream ms = new MemoryStream())
            {
                int read;
                while ((read = stream.Read(buffer, 0, buffer.Length)) > 0)
                {
                    ms.Write(buffer, 0, read);
                }
                return ms.ToArray();
            }
        }

问题: 当我通过iPhone上传我的照片时,POST成功了。返回新的图像ID,我可以看到在数据库中创建的新记录。 但是当我尝试将二进制文件从DB记录转换为Image Stream时:我收到错误: “找不到适合完成此操作的成像组件。”

似乎MemoryStream已损坏。

//photoBytes from database   
MemoryStream photoStream = new MemoryStream(photoBytes)
    //Error happened here
    var photoDecoder = BitmapDecoder.Create(
                    photoStream,
                    BitmapCreateOptions.PreservePixelFormat,
                    BitmapCacheOption.None);

另外,只有在通过WCF Restful服务上传图像时才会出现错误。 如果图像是通过网络表格上传的,它的效果非常好。

问题:

  1. 我做错了什么或错过了什么?

  2. 如何编写测试客户端来测试此上传API?

  3. 非常感谢

1 个答案:

答案 0 :(得分:2)

上面的代码实际上有效。 我错过的部分是您需要在web.config

中将其设置为“流式”的transferModel

测试代码:

static void Main()
        {
            string filePath = @"C:\Users\Dizzy\Desktop\600.png";

            string url = "http://localhost:13228/ApiRestful.svc/AddDealImage/96";

            HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
            request.Accept = "text/xml";
            request.Method = "POST";

            using (Stream fileStream = File.OpenRead(filePath))
            using (Stream requestStream = request.GetRequestStream())
            {
                int bufferSize = 1024;
                byte[] buffer = new byte[bufferSize];
                int byteCount = 0;
                while ((byteCount = fileStream.Read(buffer, 0, bufferSize)) > 0)
                {
                    requestStream.Write(buffer, 0, byteCount);
                }
            }

            string result;

            using (WebResponse response = request.GetResponse())
            using (StreamReader reader = new StreamReader(response.GetResponseStream()))
            {
                result = reader.ReadToEnd();
            }

            Console.WriteLine(result);
        }