我正在尝试找出如何使用jQuery根据该元素的数据属性将CSS类正确地应用于HTML元素。
我要实现的目标如下:
我当前遇到的问题是,一旦选择了一个以上的“水果”(即先前选定的元素),即使它具有一个或多个选定的水果,也会被选中。
$('a.fruit').click(function() {
$(this).toggleClass("active");
var fruits = $(this).data("fruit");
$("div.store[data-fruits~='" + fruits + "']").toggleClass("active");
});
body {
margin: auto;
max-width: 40em;
font-family: "Segoe UI";
background-color: #FFFFFF;
}
ul {
list-style-type: none;
padding: 0;
}
.fruit.active::after {
content: "✔️";
margin-left: .5rem;
}
.store {
position: relative;
display: inline-block;
width: 10rem;
padding: 1rem;
border-radius: 1rem;
border: 1px solid black;
text-align: center;
margin: 0 0.5rem 0.5rem 0;
bottom: 0;
-webkit-transition: all .2s ease;
-moz-transition: all .2s ease;
-ms-transition: all .2s ease;
-o-transition: all .2s ease;
transition: all .2s ease;
}
.store span {
display: block;
font-weight: bold;
width: 100%;
margin-bottom: 1rem;
text-decoration: underline;
}
.store-container {
position: relative;
}
.store.active {
position: relative;
box-shadow: 3px 3px 5px grey;
bottom: 5px;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div>
<h1>
Fruit Selector:
</h1>
<ul>
<li>
<a class="fruit" data-fruit="all">? All Fruits</a>
</li>
<li>
<a class="fruit" data-fruit="banana">? Banana</a>
</li>
<li>
<a class="fruit" data-fruit="apple">? Apple</a>
</li>
<li>
<a class="fruit" data-fruit="orange">? Orange</a>
</li>
<li>
<a class="fruit" data-fruit="grape">? Grape</a>
</li>
<li>
<a class="fruit" data-fruit="peach">? Peach</a>
</li>
</ul>
<h1>Stores:</h1>
<div class="store-container">
<div class="store" data-fruits="banana apple orange grape peach">
<span>Store A</span>?????
</div>
<div class="store" data-fruits="banana apple orange grape">
<span>Store B</span>????
</div>
<div class="store" data-fruits="banana apple orange">
<span>Store C</span>???
</div>
<div class="store" data-fruits="banana apple">
<span>Store D</span>??
</div>
<div class="store" data-fruits="banana">
<span>Store D</span>?
</div>
<div class="store" data-fruits="apple orange grape peach">
<span>Store E</span>????
</div>
<div class="store" data-fruits="orange grape peach">
<span>Store F</span>???
</div>
<div class="store" data-fruits="grape peach">
<span>Store G</span>??
</div>
<div class="store" data-fruits="peach">
<span>Store H</span>?
</div>
</div>
</div>
到目前为止,我的示例代码请参考JSFiddle。
提前感谢您提供有关此问题的指导。
编辑:
JSFiddle和Funk Doc的解决方案。
答案 0 :(得分:0)
我用了你的小提琴。这可能有点冗长,但似乎可行。每次单击以帮助解决您的问题时,我都会从.store中删除活动类。
$('a.fruit').click(function () {
$(this).toggleClass("active");
if ($('.fruit[data-fruit="all"]').hasClass('active')) {
$(".store").addClass("active");
} else {
$(".store").removeClass("active");
$('a.fruit').each(function () {
if ($(this).hasClass("active")) {
var fruit = $(this).data("fruit");
$(".store").each(function () {
if ($(this).data("fruits").includes(fruit)) {
$(this).addClass("active");
}
});
}
});
}
});