Question

尝试从对象的可观察数组迭代* ngFor时出现错误

我使用Angular 8

聊天消息服务

private chatMessages = [];
private chatMessagesStream = new BehaviorSubject(this.chatMessages);

getMessages(): Observable<any> {
   return this.chatMessagesStream.asObservable();
}


addMessage(chatMessage) {
    this.chatMessages.push(chatMessage);
    this.chatMessagesStream.next(this.chatMessages);
}

聊天视图组件

private chatMessages:Observable<Array<any>>;

constructor(
   private chatMessagesService: ChatMessagesService) {
}

ngAfterViewInit() {
    this.chatMessagesService.getMessages().subscribe(messages => {
      this.chatMessages = messages;
      this.scrollMessagesToBottom(true);
    });
}

聊天HTML模板

<div class="row conpeek_message_chat_row" *ngFor="let chatMessage of chatMessages | async ">
...
</div>

在初始化组件之后，我在控制台中遇到问题，这可能是什么问题？

ERROR Error: InvalidPipeArgument: '[object Object]' for pipe 'AsyncPipe'

Answer 1

删除异步管道

由于chatMessages是不可观察的，因此它包含纯值。

this.chatMessagesService.getMessages().subscribe(messages => {
    this.chatMessages = messages; // <------- HERE , you are assigning value
    this.scrollMessagesToBottom(true);
});

如果要保持异步管道，则必须为chatMessages分配observable，如下所示：

this.chatMessages = this.chatMessagesService.getMessages();

从对象的可观察数组迭代* ngFor时如何修复InvalidPipeArgument错误

1 个答案: