出于某种原因,当我尝试双重缓冲我的Java小程序时,它显示一个白色正方形,即使我没有告诉它。另外,如果我尝试在start()中放置一个循环,即使repaint()在最后,我也只得到一个白色的屏幕。
/**
* @(#)vo4k.java
*
* vo4k Applet application
*
* @author William Starkovich
* @version 1.00 2009/2/21
*/
import java.awt.*;
import java.applet.*;
import java.awt.event.*;
import java.awt.image.*;
public class vo4k extends Applet implements KeyListener
{
obj p1, e1;
boolean[] keys;
boolean end = false;
Graphics g2d;
Dimension size;
Image buf;
public void init()
{
keys = new boolean[256];
for(int i = 0; i < 256; i++)
keys[i] = false;
addKeyListener(this);
p1 = new obj();
p1.x = 0;
size = getSize();
buf = createImage(size.width,size.height);
g2d = buf.getGraphics();
}
public void keyTyped(KeyEvent e) {}
public void keyPressed(KeyEvent e) {keys[e.getKeyCode()] = true;}
public void keyReleased(KeyEvent e) {keys[e.getKeyCode()] = false;}
public void controls()
{
if(keys[KeyEvent.VK_SPACE])
end = true;
if(keys[KeyEvent.VK_W])
p1.x += 10;
}
public void start()
{
// while(!end)
// {
// }
}
public void paint(Graphics g)
{
controls();
//g2d = (Graphics2D) g;
g2d.setColor(Color.RED);
g2d.fillRect(0,0,size.width,size.height);
g2d.setColor(Color.BLUE);
g2d.drawString("Welcome 2 Java!!", (int) 50, 60 );
//g2d.drawString("Welcome to Java!!", (int) p1.x, 60 );
g.drawImage(buf, 0, 0, this);
repaint();
}
}
class obj
{
double x,y,l,a,s;
}
答案 0 :(得分:1)
在paint方法中检查大小。如果大小已更改,请创建一个新图像,然后绘制到该图像,并存储新的大小信息。另外,不要调用重绘,因为你只是要进行绘制的递归调用。
如果在start方法中放置一个无限循环,则线程永远不会退出start方法。
public void paint(Graphics g)
{
controls();
Dimension currentSize = getSize();
if ( ! currentSize.equals(size) ) {
size = currentSize;
buf = createImage(size.width,size.height);
g2d = buf.getGraphics();
}
//g2d = (Graphics2D) g;
g2d.setColor(Color.RED);
g2d.fillRect(0,0,size.width,size.height);
g2d.setColor(Color.BLUE);
g2d.drawString("Welcome 2 Java!!", (int) 50, 60 );
//g2d.drawString("Welcome to Java!!", (int) p1.x, 60 );
g.drawImage(buf, 0, 0, this);
}