我有一个包含用户名和密码字段的表。现在我不希望密码完全存储为用户输入的字符串。我希望将此字段加密或转换为GUID,因此没有人(包括处理SQL的人)可以看到它。 如果用户丢失了密码,他必须拿出一个新密码,并在表格中更新。 我有什么想法可以实现这个目标吗?
答案 0 :(得分:1)
OWASP guidelines说要使用单向哈希来存储密码。
本文介绍了如何在ASP.NET中使用http://www.15seconds.com/issue/000217.htm
(你没有提到你用来连接服务器的技术,所以我猜测了ASP.NET。)
答案 1 :(得分:1)
您可以使用hashbytes来执行此操作。像这样:假设密码= admin
DECLARE @dummy nvarchar(4000);
select @dummy = CONVERT(nvarchar(4000),'admin');
SELECT HashBytes('SHA1', @dummy);
答案 2 :(得分:1)
CREATE FUNCTION dbo.fnInitRc4
(
@Pwd VARCHAR(256)
)
RETURNS @Box TABLE (i TINYINT, v TINYINT)
AS
BEGIN
DECLARE @Key TABLE (i TINYINT, v TINYINT)
DECLARE @Index SMALLINT,
@PwdLen TINYINT
SELECT @Index = 0,
@PwdLen = LEN(@Pwd)
WHILE @Index <= 255
BEGIN
INSERT @Key
(
i,
v
)
VALUES (
@Index,
ASCII(SUBSTRING(@Pwd, @Index % @PwdLen + 1, 1))
)
INSERT @Box
(
i,
v
)
VALUES (
@Index,
@Index
)
SELECT @Index = @Index + 1
END
DECLARE @t TINYINT,
@b SMALLINT
SELECT @Index = 0,
@b = 0
WHILE @Index <= 255
BEGIN
SELECT @b = (@b + b.v + k.v) % 256
FROM @Box AS b
INNER JOIN @Key AS k ON k.i = b.i
WHERE b.i = @Index
SELECT @t = v
FROM @Box
WHERE i = @Index
UPDATE b1
SET b1.v = (SELECT b2.v FROM @Box b2 WHERE b2.i = @b)
FROM @Box b1
WHERE b1.i = @Index
UPDATE @Box
SET v = @t
WHERE i = @b
SELECT @Index = @Index + 1
END
RETURN
END
此功能执行加密/解密部分
CREATE FUNCTION dbo.fnEncDecRc4
(
@Pwd VARCHAR(256),
@Text VARCHAR(8000)
)
RETURNS VARCHAR(8000)
AS
BEGIN
DECLARE @Box TABLE (i TINYINT, v TINYINT)
INSERT @Box
(
i,
v
)
SELECT i,
v
FROM dbo.fnInitRc4(@Pwd)
DECLARE @Index SMALLINT,
@i SMALLINT,
@j SMALLINT,
@t TINYINT,
@k SMALLINT,
@CipherBy TINYINT,
@Cipher VARCHAR(8000)
SELECT @Index = 1,
@i = 0,
@j = 0,
@Cipher = ''
WHILE @Index <= DATALENGTH(@Text)
BEGIN
SELECT @i = (@i + 1) % 256
SELECT @j = (@j + b.v) % 256
FROM @Box b
WHERE b.i = @i
SELECT @t = v
FROM @Box
WHERE i = @i
UPDATE b
SET b.v = (SELECT w.v FROM @Box w WHERE w.i = @j)
FROM @Box b
WHERE b.i = @i
UPDATE @Box
SET v = @t
WHERE i = @j
SELECT @k = v
FROM @Box
WHERE i = @i
SELECT @k = (@k + v) % 256
FROM @Box
WHERE i = @j
SELECT @k = v
FROM @Box
WHERE i = @k
SELECT @CipherBy = ASCII(SUBSTRING(@Text, @Index, 1)) ^ @k,
@Cipher = @Cipher + CHAR(@CipherBy)
SELECT @Index = @Index +1
END
RETURN @Cipher
END
这是彼得实施的,但它有助于你................