我想知道您是否可以使用XSL导出到CSV到特定列。例如,在此示例中,某些员工缺少电子邮件,电话号码或部门。但是我希望结果是,如果缺少元素,则将其留空。
<Employees>
<Employee>
<EmployeeID>1</EmployeeID>
<EmpName>Homer Simpson</EmpName>
<Department>IT1</Department>
<PhNo>9111111111</PhNo>
<Email>Homer.Simpson@gmail.com</Email>
<Salary>99999</Salary>
</Employee>
<Employee>
<EmployeeID>2</EmployeeID>
<EmpName>John Smith</EmpName>
<Department>IT2</Department>
<PhNo>9222222222</PhNo>
<Email>smith@gmail.com</Email>
<Salary>99999</Salary>
</Employee>
<Employee>
<EmployeeID>3</EmployeeID>
<EmpName>Marge Simpson</EmpName>
<Department>IT3</Department>
<Salary>99999</Salary>
</Employee>
<Employee>
<EmployeeID>4</EmployeeID>
<EmpName>Bruce Wayne</EmpName>
<Department>IT4</Department>
<Email>batman@gmail.com</Email>
</Employee>
</Employees>
current xsl
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" />
<xsl:variable name="separator" select="';'" />
<xsl:variable name="newline" select="' '" />
<xsl:template match="/">
<xsl:for-each select="Employees/Employee">
<xsl:value-of select="EmployeeID" />
<xsl:text>,</xsl:text>
<xsl:value-of select="EmpName"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="Department"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="PhNo"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="Email"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="Salary"/>