如何用括号替换字符串的最后一位
考虑一个具有A列的表
A
-------
12345
123455
123567
1234
预期结果:
1234(5)
12345(5)
12356(7)
123(4)
答案 0 :(得分:3)
这里有两个选项:
substr
的人,SQL> with test (a) as
2 (select 12345 from dual union all
3 select 1234 from dual union all
4 select 123567 from dual
5 )
6 select a,
7 substr(a, 1, length(a) - 1) || '(' || substr(a, -1) || ')' result,
8 regexp_replace(a, '(.)$', '(\1)') result2
9 from test;
A RESULT RESULT2
---------- -------------------- --------------------
12345 1234(5) 1234(5)
1234 123(4) 123(4)
123567 12356(7) 12356(7)
SQL>