我编写了一个python脚本，用于查询数据库并以HTML表格格式显示数据。如何获取此代码以表格形式显示在电子邮件中？
我尝试将代码粘贴到第二个脚本（EMAIL）的html标签内，但它不只读取python代码HTML。
import pyodbc
import cgi
def htmlTop():
print("""Content-type:text/html\n\n
<!DOCTYPE html>
<html lang='en'>
<head>
<meta charset="utf-8"/>
<title>My Tabmle</title>
</head>
<body>""")
def selectCOAStatus(cnxn, cursor):
cursor.execute('''SELECT * from mytable''')
data = cursor.fetchall()
return data
def htmlTail():
print("""</body>
</html>""")
def connectDB():
conn_str = (
r'DRIVER={SQL Server};'
r'SERVER=test;'
r'DATABASE=test;'
r'Trusted_Connection=yes;'
)
cnxn = pyodbc.connect(conn_str)
cursor = cnxn.cursor()
return cnxn, cursor
def displayData(data):
print("<table border='1'")
print("<tr>")
print("<th>Date</th>")
print("<th>Count</th>")
print("<th>Status</th>")
print("</tr>")
for row in data:
print("<tr>")
print("<td>{0}</td>".format(row[0]))
print("<td>{0}</td>".format(row[1]))
print("<td>{0}</td>".format(row[2]))
print("</tr>")
print("</table>")
if __name__ == "__main__":
try:
htmlTop()
cnxn, cursor = connectDB()
data = selectCOAStatus(cnxn, cursor)
cursor.close()
displayData(data)
htmlTail()
except:
cgi.print_exception()
电子邮件代码
导入smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
# me == my email address
# you == recipient's email address
me = "test@aol.com"
you = "test@aol.com"
# Create message container - the correct MIME type is
multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = "Link"
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML
version).
text = "Hi!\nHow are you?\nHere is the link you
wanted:\nhttp://www.python.org"
html = htmlTop()
# Record the MIME types of both parts - text/plain and
text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message,
in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
s = smtplib.SMTP('email.fpl.com')
# sendmail function takes 3 arguments: sender's address,
recipient's address
# and message to send - here it is sent as one string.
s.sendmail(me, you, msg.as_string())
s.quit()
我希望此HTML表显示在我的电子邮件正文中。
答案 0 :(得分：1)
尝试
{
"version": "2.0.0",
"presentation": {
"echo": true,
"reveal": "always",
"focus": true,
"panel": "new"
},
"tasks": [
{
"label": "cmake",
"type": "shell",
"command": "cmake -DCMAKE_BUILD_TYPE=Debug ..",
"options": {
"cwd": "${workspaceRoot}/build"
}
},
{
"label": "make",
"type": "shell",
"options": {
"cwd": "${workspaceRoot}/build"
},
"command": "make -j8",
"dependsOn": [
"cmake"
],
"group": {
"kind": "build",
"isDefault": true
}
}
]
}
也是一种用于HTML电子邮件的更简单方法
print("<td>%s</td>" % row[0] )
答案 1 :(得分：0)
我能够将数据放入表中。我修复了for循环遍历所有行并返回值的问题。虽然它只返回一行，而我的查询却返回其他多行。为什么会这样？
导入pyodbc 进口CGI 导入html
conn_str = (
r'DRIVER=test'
r'SERVER=test;'
r'DATABASE=test;'
r'Trusted_Connection=yes;'
)
cnxn = pyodbc.connect(conn_str)
cursor = cnxn.cursor()
cursor.execute('''SELECT * from my table '''
for row in cursor:
html_code = """
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
<body>
<table border='1'
<tr>
<th>Date</th>
<th>Count</th>
<th>Status</th>
</tr>
<tr>
<td>{}</td>
<td>{}</td>
<td>{}</td>
</tr>
</table>
</body>
</html>""".format(row[0],row[1],row[2])
print(html_code)
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
# me == my email address
# you == recipient's email address
me = "test@aol.com"
you = "test@aol.com"
# Create message container - the correct MIME type is
multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = "Link"
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML version).
text = "Hi!\nHow are you?\nHere is the link you
wanted:\nhttp://www.python.org"
html = html_code
# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this
case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
s = smtplib.SMTP('email.fpl.com')
# sendmail function takes 3 arguments: sender's address, recipient's
address
# and message to send - here it is sent as one string.
s.sendmail(me, you, msg.as_string())
s.quit()